Answered

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A soft ball is hit at the speed of 25m/s.If the initial velocity of the ball is40m/s.​

Sagot :

When the ball reaches the highest point, its velocity will be zero. So final velocity is :

v=0m/s

Here, the time to reach highest point is equal to time to hit ground from highest point.

Consider upward motion, the acceleration of the ball is

a=−g=−9.8m/s2

(minus for motion opposite to gravity)

If It be the required time.

Using

v=u+at,0=25+(−9.8)t⟹ t=2.5s

Thus the ball hits the ground after

2.5

seconds after reaching its highest point.

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