Answered

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Enter the resulting polynomial in standard form using [tex]${ }^{\wedge}$[/tex] for exponents (e.g., [tex]$x^{\wedge}2$[/tex] for [tex]$x^2$[/tex]).

Polynomial: [tex]$10y^2 + 14$[/tex]

2 [tex]$\square$[/tex]

Sagot :

GinnyAnswer
Sure, I can explain the process of writing the polynomial in standard form.

### Step-by-Step Solution:

1. Identify the polynomial: The polynomial given is [tex]\(10y^2 + 14\)[/tex].

2. Determine the standard form: The standard form of a polynomial arranges the terms in descending order of their exponents. In this case, we have two terms:
- The term with [tex]\( y^2 \)[/tex] is [tex]\(10y^2\)[/tex].
- The constant term is [tex]\(14\)[/tex].

3. Write the polynomial: Since there are no other terms with different exponents, the given expression is already in the standard form.

### Final Answer:
The polynomial in standard form is [tex]\( \boxed{10 y^{\wedge}2 + 14} \)[/tex].
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