Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Let's analyze each student's claim about the quadratic function [tex]\( f(x) = (x + 3)(x + 5) \)[/tex].
1. Jeremiah's Claim: The [tex]\( y \)[/tex]-intercept is at [tex]\( (15,0) \)[/tex]
- To find the [tex]\( y \)[/tex]-intercept, we evaluate [tex]\( f(x) \)[/tex] at [tex]\( x = 0 \)[/tex].
[tex]\[ f(0) = (0 + 3)(0 + 5) = 3 \times 5 = 15 \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is [tex]\( (0, 15) \)[/tex]. Jeremiah's claim is incorrect as he interchanged the coordinates.
2. Lindsay's Claim: The [tex]\( x \)[/tex]-intercepts are at [tex]\( (-3,0) \)[/tex] and [tex]\( (5,0) \)[/tex]
- To find the [tex]\( x \)[/tex]-intercepts, we solve [tex]\( f(x) = 0 \)[/tex].
[tex]\[ (x + 3)(x + 5) = 0 \][/tex]
This gives us [tex]\( x = -3 \)[/tex] and [tex]\( x = -5 \)[/tex]. Therefore, the [tex]\( x \)[/tex]-intercepts are at [tex]\( (-3,0) \)[/tex] and [tex]\( (-5,0) \)[/tex]. Lindsay's claim is incorrect because she gave [tex]\( (5,0) \)[/tex] instead of [tex]\( (-5,0) \)[/tex].
3. Stephen's Claim: The vertex is at [tex]\( (-4, -1) \)[/tex]
- The vertex of a parabola given in standard form [tex]\( ax^2 + bx + c \)[/tex] can be found using the formula [tex]\(\left( -\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right) \)[/tex].
Expanding [tex]\( f(x) \)[/tex] we get:
[tex]\[ (x + 3)(x + 5) = x^2 + 8x + 15 \][/tex]
Here, [tex]\( a = 1 \)[/tex], [tex]\( b = 8 \)[/tex]. The [tex]\( x \)[/tex]-coordinate of the vertex is:
[tex]\[ x = -\frac{b}{2a} = -\frac{8}{2 \cdot 1} = -4 \][/tex]
Substitute [tex]\( x = -4 \)[/tex] into [tex]\( f(x) \)[/tex] to find the [tex]\( y \)[/tex]-coordinate:
[tex]\[ f(-4) = (-4 + 3)(-4 + 5) = (-1)(1) = -1 \][/tex]
Thus, the vertex is indeed at [tex]\( (-4, -1) \)[/tex]. Stephen's claim is correct.
4. Alexis's Claim: The midpoint between the [tex]\( x \)[/tex]-intercepts is at [tex]\( (4,0) \)[/tex]
- The midpoint between the [tex]\( x \)[/tex]-intercepts [tex]\((-3,0)\)[/tex] and [tex]\((-5,0)\)[/tex] is:
[tex]\[ \left( \frac{-3 + (-5)}{2}, 0 \right) = \left( \frac{-8}{2}, 0 \right) = (-4, 0) \][/tex]
Alexis's claim is incorrect because the correct midpoint is [tex]\( (-4,0) \)[/tex] not [tex]\( (4,0) \)[/tex].
After analyzing all the claims, the correct one is:
The claim by Stephen is correct.
1. Jeremiah's Claim: The [tex]\( y \)[/tex]-intercept is at [tex]\( (15,0) \)[/tex]
- To find the [tex]\( y \)[/tex]-intercept, we evaluate [tex]\( f(x) \)[/tex] at [tex]\( x = 0 \)[/tex].
[tex]\[ f(0) = (0 + 3)(0 + 5) = 3 \times 5 = 15 \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is [tex]\( (0, 15) \)[/tex]. Jeremiah's claim is incorrect as he interchanged the coordinates.
2. Lindsay's Claim: The [tex]\( x \)[/tex]-intercepts are at [tex]\( (-3,0) \)[/tex] and [tex]\( (5,0) \)[/tex]
- To find the [tex]\( x \)[/tex]-intercepts, we solve [tex]\( f(x) = 0 \)[/tex].
[tex]\[ (x + 3)(x + 5) = 0 \][/tex]
This gives us [tex]\( x = -3 \)[/tex] and [tex]\( x = -5 \)[/tex]. Therefore, the [tex]\( x \)[/tex]-intercepts are at [tex]\( (-3,0) \)[/tex] and [tex]\( (-5,0) \)[/tex]. Lindsay's claim is incorrect because she gave [tex]\( (5,0) \)[/tex] instead of [tex]\( (-5,0) \)[/tex].
3. Stephen's Claim: The vertex is at [tex]\( (-4, -1) \)[/tex]
- The vertex of a parabola given in standard form [tex]\( ax^2 + bx + c \)[/tex] can be found using the formula [tex]\(\left( -\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right) \)[/tex].
Expanding [tex]\( f(x) \)[/tex] we get:
[tex]\[ (x + 3)(x + 5) = x^2 + 8x + 15 \][/tex]
Here, [tex]\( a = 1 \)[/tex], [tex]\( b = 8 \)[/tex]. The [tex]\( x \)[/tex]-coordinate of the vertex is:
[tex]\[ x = -\frac{b}{2a} = -\frac{8}{2 \cdot 1} = -4 \][/tex]
Substitute [tex]\( x = -4 \)[/tex] into [tex]\( f(x) \)[/tex] to find the [tex]\( y \)[/tex]-coordinate:
[tex]\[ f(-4) = (-4 + 3)(-4 + 5) = (-1)(1) = -1 \][/tex]
Thus, the vertex is indeed at [tex]\( (-4, -1) \)[/tex]. Stephen's claim is correct.
4. Alexis's Claim: The midpoint between the [tex]\( x \)[/tex]-intercepts is at [tex]\( (4,0) \)[/tex]
- The midpoint between the [tex]\( x \)[/tex]-intercepts [tex]\((-3,0)\)[/tex] and [tex]\((-5,0)\)[/tex] is:
[tex]\[ \left( \frac{-3 + (-5)}{2}, 0 \right) = \left( \frac{-8}{2}, 0 \right) = (-4, 0) \][/tex]
Alexis's claim is incorrect because the correct midpoint is [tex]\( (-4,0) \)[/tex] not [tex]\( (4,0) \)[/tex].
After analyzing all the claims, the correct one is:
The claim by Stephen is correct.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.