Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Type the correct answer in the box. Round your answer to the nearest hundredth.

Element [tex]\( X \)[/tex] has two isotopes. The table gives information about these isotopes.

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
Isotope & Atomic Mass (amu) & Abundance (\%) \\
\hline
X-63 & 62.9296 & 69.15 \\
\hline
X-65 & 64.9278 & 30.85 \\
\hline
\end{tabular}
\][/tex]

The average atomic mass of element [tex]\( X \)[/tex] is [tex]\(\square\)[/tex] amu.

Sagot :

To find the average atomic mass of element [tex]\( X \)[/tex], we need to use the masses of the isotopes and their respective abundances. The average atomic mass is calculated using the formula for the weighted average:

[tex]\[ \text{average atomic mass} = \left( \frac{\text{mass of isotope 1} \times \text{abundance of isotope 1}}{100} \right) + \left( \frac{\text{mass of isotope 2} \times \text{abundance of isotope 2}}{100} \right) \][/tex]

Firstly, let's identify the masses and abundances given:
- Isotope X-63 has a mass of 62.9296 amu and an abundance of 69.15%.
- Isotope X-65 has a mass of 64.9278 amu and an abundance of 30.85%.

Now, convert the percentage abundances to decimal form by dividing by 100:
- The abundance of X-63 is [tex]\( \frac{69.15}{100} = 0.6915 \)[/tex].
- The abundance of X-65 is [tex]\( \frac{30.85}{100} = 0.3085 \)[/tex].

Next, we calculate the contribution of each isotope to the average atomic mass:
- Contribution of X-63: [tex]\( 62.9296 \times 0.6915 = 43.5048 \)[/tex]
- Contribution of X-65: [tex]\( 64.9278 \times 0.3085 = 20.04695 \)[/tex]

Adding these contributions together gives the average atomic mass:
[tex]\[ 43.5048 + 20.04695 = 63.55175 \][/tex]

Finally, we round this result to the nearest hundredth:
[tex]\[ 63.55175 \approx 63.55 \][/tex]

Therefore, the average atomic mass of element [tex]\( X \)[/tex] is [tex]\( 63.55 \)[/tex] amu.