At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To find the midpoint of a line segment with endpoints [tex]\( G(14, 3) \)[/tex] and [tex]\( H(10, -6) \)[/tex], we use the midpoint formula. The midpoint formula is:
[tex]\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]
where [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] are the coordinates of the two endpoints.
Here, the coordinates of [tex]\( G \)[/tex] are [tex]\( (14, 3) \)[/tex] and the coordinates of [tex]\( H \)[/tex] are [tex]\( (10, -6) \)[/tex].
Let's calculate the midpoint:
1. Calculate the [tex]\(x\)[/tex]-coordinate of the midpoint:
[tex]\[ \frac{14 + 10}{2} = \frac{24}{2} = 12 \][/tex]
2. Calculate the [tex]\(y\)[/tex]-coordinate of the midpoint:
[tex]\[ \frac{3 + (-6)}{2} = \frac{3 - 6}{2} = \frac{-3}{2} = -1.5 \][/tex]
So, the coordinates of the midpoint are:
[tex]\[ \left(12, -1.5\right) \][/tex]
Therefore, the correct answer is:
[tex]\[ \text{C.} \left(12, -\frac{3}{2}\right) \][/tex]
[tex]\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]
where [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] are the coordinates of the two endpoints.
Here, the coordinates of [tex]\( G \)[/tex] are [tex]\( (14, 3) \)[/tex] and the coordinates of [tex]\( H \)[/tex] are [tex]\( (10, -6) \)[/tex].
Let's calculate the midpoint:
1. Calculate the [tex]\(x\)[/tex]-coordinate of the midpoint:
[tex]\[ \frac{14 + 10}{2} = \frac{24}{2} = 12 \][/tex]
2. Calculate the [tex]\(y\)[/tex]-coordinate of the midpoint:
[tex]\[ \frac{3 + (-6)}{2} = \frac{3 - 6}{2} = \frac{-3}{2} = -1.5 \][/tex]
So, the coordinates of the midpoint are:
[tex]\[ \left(12, -1.5\right) \][/tex]
Therefore, the correct answer is:
[tex]\[ \text{C.} \left(12, -\frac{3}{2}\right) \][/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.