At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To determine whether the equation [tex]\( x + 5 = y^2 \)[/tex] defines [tex]\( y \)[/tex] as a function of [tex]\( x \)[/tex], we need to consider the definition of a function. A function [tex]\( y = f(x) \)[/tex] assigns exactly one output [tex]\( y \)[/tex] for each input [tex]\( x \)[/tex].
Given the equation:
[tex]\[ x + 5 = y^2 \][/tex]
First, we solve for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex]:
[tex]\[ y^2 = x + 5 \][/tex]
[tex]\[ y = \pm \sqrt{x + 5} \][/tex]
From this, we see that for each value of [tex]\( x \)[/tex], there are two possible values of [tex]\( y \)[/tex]:
[tex]\[ y = \sqrt{x + 5} \][/tex]
and
[tex]\[ y = -\sqrt{x + 5} \][/tex]
This indicates that for any given [tex]\( x \)[/tex], there are two corresponding [tex]\( y \)[/tex] values (one positive and one negative). Thus, [tex]\( y \)[/tex] is not uniquely determined by [tex]\( x \)[/tex].
Since a function must assign exactly one output for each input, the equation [tex]\( x + 5 = y^2 \)[/tex] does not define [tex]\( y \)[/tex] as a function of [tex]\( x \)[/tex]. Therefore, the correct answer is:
No
Given the equation:
[tex]\[ x + 5 = y^2 \][/tex]
First, we solve for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex]:
[tex]\[ y^2 = x + 5 \][/tex]
[tex]\[ y = \pm \sqrt{x + 5} \][/tex]
From this, we see that for each value of [tex]\( x \)[/tex], there are two possible values of [tex]\( y \)[/tex]:
[tex]\[ y = \sqrt{x + 5} \][/tex]
and
[tex]\[ y = -\sqrt{x + 5} \][/tex]
This indicates that for any given [tex]\( x \)[/tex], there are two corresponding [tex]\( y \)[/tex] values (one positive and one negative). Thus, [tex]\( y \)[/tex] is not uniquely determined by [tex]\( x \)[/tex].
Since a function must assign exactly one output for each input, the equation [tex]\( x + 5 = y^2 \)[/tex] does not define [tex]\( y \)[/tex] as a function of [tex]\( x \)[/tex]. Therefore, the correct answer is:
No
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.