Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To determine which linear function represents a slope of [tex]\(\frac{1}{4}\)[/tex], we need to examine the slopes derived from the two data sets provided.
First, let's understand what slope represents. The slope [tex]\(m\)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] on a straight line is calculated using the formula:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
The two data sets given are:
1.
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline 3 & -11 \\ \hline 6 & 1 \\ \hline 9 & 13 \\ \hline 12 & 25 \\ \hline \end{tabular} \][/tex]
2.
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline -5 & 32 \\ \hline -1 & 24 \\ \hline 3 & 16 \\ \hline 7 & 8 \\ \hline \end{tabular} \][/tex]
Let's calculate the slopes for these points in both data sets.
For the first data set:
1. Between [tex]\((3, -11)\)[/tex] and [tex]\((6, 1)\)[/tex]:
[tex]\[ m = \frac{1 - (-11)}{6 - 3} = \frac{12}{3} = 4 \][/tex]
2. Between [tex]\((6, 1)\)[/tex] and [tex]\((9, 13)\)[/tex]:
[tex]\[ m = \frac{13 - 1}{9 - 6} = \frac{12}{3} = 4 \][/tex]
3. Between [tex]\((9, 13)\)[/tex] and [tex]\((12, 25)\)[/tex]:
[tex]\[ m = \frac{25 - 13}{12 - 9} = \frac{12}{3} = 4 \][/tex]
So, the slopes between consecutive points in the first data set are consistently 4.
For the second data set:
1. Between [tex]\((-5, 32)\)[/tex] and [tex]\((-1, 24)\)[/tex]:
[tex]\[ m = \frac{24 - 32}{-1 - (-5)} = \frac{-8}{4} = -2 \][/tex]
2. Between [tex]\((-1, 24)\)[/tex] and [tex]\((3, 16)\)[/tex]:
[tex]\[ m = \frac{16 - 24}{3 - (-1)} = \frac{-8}{4} = -2 \][/tex]
3. Between [tex]\((3, 16)\)[/tex] and [tex]\((7, 8)\)[/tex]:
[tex]\[ m = \frac{8 - 16}{7 - 3} = \frac{-8}{4} = -2 \][/tex]
So, the slopes between consecutive points in the second data set are consistently -2.
Comparing the slopes:
- The first data set has slopes of 4.
- The second data set has slopes of -2.
Neither of these consistently represents a slope of [tex]\(\frac{1}{4}\)[/tex]. There is no linear function in these data sets that has a slope of [tex]\(\frac{1}{4}\)[/tex]. The slopes are either 4 or -2, not [tex]\(\frac{1}{4}\)[/tex].
First, let's understand what slope represents. The slope [tex]\(m\)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] on a straight line is calculated using the formula:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
The two data sets given are:
1.
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline 3 & -11 \\ \hline 6 & 1 \\ \hline 9 & 13 \\ \hline 12 & 25 \\ \hline \end{tabular} \][/tex]
2.
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline -5 & 32 \\ \hline -1 & 24 \\ \hline 3 & 16 \\ \hline 7 & 8 \\ \hline \end{tabular} \][/tex]
Let's calculate the slopes for these points in both data sets.
For the first data set:
1. Between [tex]\((3, -11)\)[/tex] and [tex]\((6, 1)\)[/tex]:
[tex]\[ m = \frac{1 - (-11)}{6 - 3} = \frac{12}{3} = 4 \][/tex]
2. Between [tex]\((6, 1)\)[/tex] and [tex]\((9, 13)\)[/tex]:
[tex]\[ m = \frac{13 - 1}{9 - 6} = \frac{12}{3} = 4 \][/tex]
3. Between [tex]\((9, 13)\)[/tex] and [tex]\((12, 25)\)[/tex]:
[tex]\[ m = \frac{25 - 13}{12 - 9} = \frac{12}{3} = 4 \][/tex]
So, the slopes between consecutive points in the first data set are consistently 4.
For the second data set:
1. Between [tex]\((-5, 32)\)[/tex] and [tex]\((-1, 24)\)[/tex]:
[tex]\[ m = \frac{24 - 32}{-1 - (-5)} = \frac{-8}{4} = -2 \][/tex]
2. Between [tex]\((-1, 24)\)[/tex] and [tex]\((3, 16)\)[/tex]:
[tex]\[ m = \frac{16 - 24}{3 - (-1)} = \frac{-8}{4} = -2 \][/tex]
3. Between [tex]\((3, 16)\)[/tex] and [tex]\((7, 8)\)[/tex]:
[tex]\[ m = \frac{8 - 16}{7 - 3} = \frac{-8}{4} = -2 \][/tex]
So, the slopes between consecutive points in the second data set are consistently -2.
Comparing the slopes:
- The first data set has slopes of 4.
- The second data set has slopes of -2.
Neither of these consistently represents a slope of [tex]\(\frac{1}{4}\)[/tex]. There is no linear function in these data sets that has a slope of [tex]\(\frac{1}{4}\)[/tex]. The slopes are either 4 or -2, not [tex]\(\frac{1}{4}\)[/tex].
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.