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Simplify: [tex]\((x-7)(6x-3)\)[/tex]

A. [tex]\(6x^2 + 21\)[/tex]

B. [tex]\(6x^2 - 45x + 21\)[/tex]

C. [tex]\(6x^2 + 39x - 21\)[/tex]

D. [tex]\(7x^2 - 10\)[/tex]


Sagot :

To simplify the expression [tex]\((x-7)(6x-3)\)[/tex], we need to use the distributive property, also known as the FOIL method (First, Outer, Inner, Last), to expand the product.

1. First: Multiply the first terms in each binomial.
[tex]\[ x \cdot 6x = 6x^2 \][/tex]

2. Outer: Multiply the outer terms in the binomials.
[tex]\[ x \cdot (-3) = -3x \][/tex]

3. Inner: Multiply the inner terms in the binomials.
[tex]\[ -7 \cdot 6x = -42x \][/tex]

4. Last: Multiply the last terms in each binomial.
[tex]\[ -7 \cdot (-3) = 21 \][/tex]

Now, we need to sum these products:
[tex]\[ 6x^2 - 3x - 42x + 21 \][/tex]

Combine the like terms ([tex]\(-3x\)[/tex] and [tex]\(-42x\)[/tex]):
[tex]\[ 6x^2 - 45x + 21 \][/tex]

Thus, the simplified expression is:
[tex]\[ 6x^2 - 45x + 21 \][/tex]

So the correct answer is:
[tex]\[ \boxed{6x^2 - 45x + 21} \][/tex]

The correct answer chooses option B:
[tex]\[ \boxed{B} \][/tex]