Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To solve for [tex]\( f(-2) \)[/tex] given the function [tex]\( f(x) = 2 \cdot 3^x \)[/tex]:
1. Substitute [tex]\( x = -2 \)[/tex] into the function:
[tex]\[ f(x) = 2 \cdot 3^x \][/tex]
So,
[tex]\[ f(-2) = 2 \cdot 3^{-2} \][/tex]
2. Simplify the exponent:
Recall that [tex]\( 3^{-2} \)[/tex] means [tex]\( \frac{1}{3^2} \)[/tex], which simplifies to [tex]\( \frac{1}{9} \)[/tex].
[tex]\[ 3^{-2} = \frac{1}{9} \][/tex]
3. Multiply by the constant 2:
[tex]\[ f(-2) = 2 \cdot \frac{1}{9} = \frac{2}{9} \][/tex]
4. Convert the fraction to its decimal form:
[tex]\( \frac{2}{9} = 0.2222222222222222 \)[/tex]
Thus,
[tex]\[ f(-2) = 0.2222222222222222 \][/tex]
Therefore, the solution is:
[tex]\( \boxed{0.2222222222222222} \)[/tex]
1. Substitute [tex]\( x = -2 \)[/tex] into the function:
[tex]\[ f(x) = 2 \cdot 3^x \][/tex]
So,
[tex]\[ f(-2) = 2 \cdot 3^{-2} \][/tex]
2. Simplify the exponent:
Recall that [tex]\( 3^{-2} \)[/tex] means [tex]\( \frac{1}{3^2} \)[/tex], which simplifies to [tex]\( \frac{1}{9} \)[/tex].
[tex]\[ 3^{-2} = \frac{1}{9} \][/tex]
3. Multiply by the constant 2:
[tex]\[ f(-2) = 2 \cdot \frac{1}{9} = \frac{2}{9} \][/tex]
4. Convert the fraction to its decimal form:
[tex]\( \frac{2}{9} = 0.2222222222222222 \)[/tex]
Thus,
[tex]\[ f(-2) = 0.2222222222222222 \][/tex]
Therefore, the solution is:
[tex]\( \boxed{0.2222222222222222} \)[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.