Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

If [tex]\(a=3\)[/tex], [tex]\(b=1\)[/tex], [tex]\(c=2\)[/tex], [tex]\(m=3\)[/tex], and [tex]\(n=4\)[/tex], then find the value of the following:

a) [tex]\(\frac{a^m \times b^n \times c^n}{m^2 \times m^5 \times (mn)^6}\)[/tex]

b) [tex]\(\frac{(a+b-c)^{m+n}}{(n-m)^{-b+c}}\)[/tex]


Sagot :

Let's solve each part step by step.

### Part (a)

Given:
- [tex]\( a = 3 \)[/tex]
- [tex]\( b = 1 \)[/tex]
- [tex]\( c = 2 \)[/tex]
- [tex]\( m = 3 \)[/tex]
- [tex]\( n = 4 \)[/tex]

We need to find the value of:
[tex]\[ \frac{a^m \times b^n \times c^n}{m^2 \times m^5 \times (m \cdot n)^6} \][/tex]

First, calculate the numerator:
[tex]\[ a^m \times b^n \times c^n \][/tex]

Substitute the given values:
[tex]\[ 3^3 \times 1^4 \times 2^4 \][/tex]

Evaluate the powers:
[tex]\[ 27 \times 1 \times 16 \][/tex]

Now, multiply these results:
[tex]\[ 27 \times 16 = 432 \][/tex]

Next, calculate the denominator:
[tex]\[ m^2 \times m^5 \times (m \cdot n)^6 \][/tex]

Substitute the given values:
[tex]\[ 3^2 \times 3^5 \times (3 \times 4)^6 \][/tex]

Evaluate the powers:
[tex]\[ 9 \times 243 \times (12)^6 \][/tex]

Calculate [tex]\( (12)^6 \)[/tex]:
[tex]\[ 12^6 = 2985984 \][/tex]

Now, multiply these results:
[tex]\[ 9 \times 243 \times 2985984 = 6530347008 \][/tex]

Finally, divide the numerator by the denominator:
[tex]\[ \frac{432}{6530347008} \approx 6.61526867516808 \times 10^{-8} \][/tex]

So the value of part (a) is approximately:
[tex]\[ 6.61526867516808 \times 10^{-8} \][/tex]

### Part (b)

Given the same values, we now need to find:
[tex]\[ \frac{(a+b-c)^{m+n}}{(n-m)^{-b+c}} \][/tex]

Substitute the given values:
[tex]\[ \frac{(3 + 1 - 2)^{3+4}}{(4 - 3)^{-1+2}} \][/tex]

Simplify inside the parentheses:
[tex]\[ \frac{(2)^7}{(1)^1} \][/tex]

Evaluate the powers:
[tex]\[ \frac{128}{1} \][/tex]

So the value of part (b) is:
[tex]\[ 128 \][/tex]

In summary:
- Part (a): [tex]\( 6.61526867516808 \times 10^{-8} \)[/tex]
- Part (b): [tex]\( 128 \)[/tex]