Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To determine the correct statement about the graph of the function [tex]\( f(x) = \log_2 x \)[/tex], let's analyze the graph step-by-step.
1. Vertical Asymptote:
- The logarithmic function [tex]\( \log_2 x \)[/tex] has a vertical asymptote where the argument of the logarithm (in this case, [tex]\( x \)[/tex]) approaches zero from the right.
- Therefore, the vertical asymptote for [tex]\( f(x) = \log_2 x \)[/tex] is at [tex]\( x = 0 \)[/tex].
2. Behavior of the Graph:
- As [tex]\( x \)[/tex] approaches 0 from the right ([tex]\( x \to 0^+ \)[/tex]), the value of [tex]\( \log_2 x \)[/tex] tends towards negative infinity. This confirms that the graph has a vertical asymptote at [tex]\( x = 0 \)[/tex].
- The function [tex]\( f(x) = \log_2 x \)[/tex] is defined only for positive [tex]\( x \)[/tex] values.
3. Sign of the Function on the Interval [tex]\( (0, 1) \)[/tex]:
- We next investigate the value of [tex]\( f(x) \)[/tex] on the interval [tex]\( (0, 1) \)[/tex]. We know that for [tex]\( x \)[/tex] in [tex]\( (0, 1) \)[/tex], [tex]\( 0 < x < 1 \)[/tex].
- For any [tex]\( x \)[/tex] between 0 and 1, [tex]\( \log_2 x \)[/tex] is negative because we are taking the logarithm base 2 of a number less than 1.
We can now address each of the statements given in the question:
A. The graph has an asymptote of [tex]\( y = 0 \)[/tex] and is increasing as [tex]\( x \)[/tex] approaches positive infinity. - This is incorrect. The asymptote is at [tex]\( x = 0 \)[/tex], not [tex]\( y = 0 \)[/tex].
B. The graph has an asymptote of [tex]\( x = 0 \)[/tex] and is negative over the interval [tex]\( (0, 1) \)[/tex]. - This statement is correct.
C. The graph has an asymptote of [tex]\( x = 0 \)[/tex] and is positive over the interval [tex]\( (0, 1) \)[/tex]. - This is incorrect. The function [tex]\( \log_2 x \)[/tex] is negative over the interval [tex]\( (0, 1) \)[/tex].
D. The graph has an asymptote of [tex]\( y = 0 \)[/tex] and is decreasing as [tex]\( x \)[/tex] approaches positive infinity. - This is incorrect. The asymptote is at [tex]\( x = 0 \)[/tex], not [tex]\( y = 0 \)[/tex], and the function is increasing as [tex]\( x \)[/tex] approaches positive infinity.
Based on this analysis, the correct answer is B. The graph has an asymptote of [tex]\( x=0 \)[/tex] and is negative over the interval [tex]\( (0,1) \)[/tex].
1. Vertical Asymptote:
- The logarithmic function [tex]\( \log_2 x \)[/tex] has a vertical asymptote where the argument of the logarithm (in this case, [tex]\( x \)[/tex]) approaches zero from the right.
- Therefore, the vertical asymptote for [tex]\( f(x) = \log_2 x \)[/tex] is at [tex]\( x = 0 \)[/tex].
2. Behavior of the Graph:
- As [tex]\( x \)[/tex] approaches 0 from the right ([tex]\( x \to 0^+ \)[/tex]), the value of [tex]\( \log_2 x \)[/tex] tends towards negative infinity. This confirms that the graph has a vertical asymptote at [tex]\( x = 0 \)[/tex].
- The function [tex]\( f(x) = \log_2 x \)[/tex] is defined only for positive [tex]\( x \)[/tex] values.
3. Sign of the Function on the Interval [tex]\( (0, 1) \)[/tex]:
- We next investigate the value of [tex]\( f(x) \)[/tex] on the interval [tex]\( (0, 1) \)[/tex]. We know that for [tex]\( x \)[/tex] in [tex]\( (0, 1) \)[/tex], [tex]\( 0 < x < 1 \)[/tex].
- For any [tex]\( x \)[/tex] between 0 and 1, [tex]\( \log_2 x \)[/tex] is negative because we are taking the logarithm base 2 of a number less than 1.
We can now address each of the statements given in the question:
A. The graph has an asymptote of [tex]\( y = 0 \)[/tex] and is increasing as [tex]\( x \)[/tex] approaches positive infinity. - This is incorrect. The asymptote is at [tex]\( x = 0 \)[/tex], not [tex]\( y = 0 \)[/tex].
B. The graph has an asymptote of [tex]\( x = 0 \)[/tex] and is negative over the interval [tex]\( (0, 1) \)[/tex]. - This statement is correct.
C. The graph has an asymptote of [tex]\( x = 0 \)[/tex] and is positive over the interval [tex]\( (0, 1) \)[/tex]. - This is incorrect. The function [tex]\( \log_2 x \)[/tex] is negative over the interval [tex]\( (0, 1) \)[/tex].
D. The graph has an asymptote of [tex]\( y = 0 \)[/tex] and is decreasing as [tex]\( x \)[/tex] approaches positive infinity. - This is incorrect. The asymptote is at [tex]\( x = 0 \)[/tex], not [tex]\( y = 0 \)[/tex], and the function is increasing as [tex]\( x \)[/tex] approaches positive infinity.
Based on this analysis, the correct answer is B. The graph has an asymptote of [tex]\( x=0 \)[/tex] and is negative over the interval [tex]\( (0,1) \)[/tex].
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.