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Considering the activity series given below for metals and nonmetals, which reaction will occur?

Activity Series:
- Metals: Al > Mn > Zn > Cr > Fe > Cd > Co > Ni > Sn > Pb > H > Sb > Bi > Cu > Ag > Pd > Hg > Pt
- Nonmetals: F > Cl > Br > I

Reactions:
1. [tex]\( 2 \text{NaBr} + \text{I}_2 \rightarrow 2 \text{NaI} + \text{Br}_2 \)[/tex]
2. [tex]\( 2 \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{Al} + \text{Fe}_2\text{O}_3 \)[/tex]
3. [tex]\( 2 \text{AgNO}_3 + \text{Ni} \rightarrow \text{Ni}\left(\text{NO}_3\right)_2 + 2 \text{Ag} \)[/tex]
4. [tex]\( \text{Pb} + \text{Zn}\left(\text{C}_2\text{H}_3\text{O}_2\right)_2 \rightarrow \text{Zn} + \text{Pb}\left(\text{C}_2\text{H}_3\text{O}_2\right)_2 \)[/tex]

Sagot :

GinnyAnswer
To determine which reactions will occur, we need to examine the reactivity of the elements involved in each reaction using the given activity series for metals and nonmetals.

1. Reaction 1:
[tex]\[ 2 \, \text{NaBr} + \text{I}_2 \rightarrow 2 \, \text{NaI} + \text{Br}_2 \][/tex]

- Iodine (I[tex]\(_2\)[/tex]) can displace Bromine (Br) if Iodine is less reactive than Bromine.
- According to the nonmetals activity series, Bromine (Br) is more reactive than Iodine (I).
- Since Iodine is less reactive, it can displace Bromine in this reaction.

Reaction 1 will occur.

2. Reaction 2:
[tex]\[ 2 \, \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow 2 \, \text{Al} + \text{Fe}_2\text{O}_3 \][/tex]

- To displace Aluminum (Al) from its oxide, Iron (Fe) must be more reactive than Aluminum.
- According to the metals activity series, Aluminum (Al) is more reactive than Iron (Fe).
- Therefore, Iron cannot displace Aluminum in this reaction.

Reaction 2 will not occur.

3. Reaction 3:
[tex]\[ 2 \, \text{AgNO}_3 + \text{Ni} \rightarrow \text{Ni}(\text{NO}_3)_2 + 2 \, \text{Ag} \][/tex]

- Nickel (Ni) can displace Silver (Ag) if Nickel is more reactive than Silver.
- According to the metals activity series, Nickel (Ni) is more reactive than Silver (Ag).
- Thus, Nickel can displace Silver in this reaction.

Reaction 3 will occur.

4. Reaction 4:
[tex]\[ \text{Pb} + \text{Zn}(\text{C}_2\text{H}_3\text{O}_2)_2 \rightarrow \text{Zn} + \text{Pb}(\text{C}_2\text{H}_3\text{O}_2)_2 \][/tex]

- Lead (Pb) can displace Zinc (Zn) if Lead is more reactive than Zinc.
- According to the metals activity series, Zinc (Zn) is more reactive than Lead (Pb).
- Therefore, Lead cannot displace Zinc in this reaction.

Reaction 4 will not occur.

Based on the above analysis:

- Reaction 1 occurs.
- Reaction 2 does not occur.
- Reaction 3 occurs.
- Reaction 4 does not occur.

The binary representation of whether the reactions occur (1 for occurrence, 0 for non-occurrence) will be:

[tex]\[ [1, 0, 1, 0] \][/tex]

Therefore, the correct and complete outcome is:

- Reaction 1: True
- Reaction 2: False
- Reaction 3: True
- Reaction 4: False
- Binary result: [1, 1, 0 ]
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