Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To identify the base-conjugate acid pair in the given reaction, it's essential to understand the concept of acid-base conjugation. In a chemical reaction involving acids and bases:
- An acid loses a proton (H⁺) to form its conjugate base.
- A base gains a proton (H⁺) to form its conjugate acid.
Let's analyze the given reaction:
[tex]\[ \text{H}_2\text{PO}_4^- + \text{H}_2\text{O} \rightarrow \text{H}_3\text{O}^+ + \text{HPO}_4^{2-} \][/tex]
From this reaction:
- Di-hydrogen phosphate ([tex]\(\text{H}_2\text{PO}_4^-\)[/tex]) is reacting with water ([tex]\(\text{H}_2\text{O}\)[/tex]).
- The product formed includes hydronium ([tex]\(\text{H}_3\text{O}^+\)[/tex]) and hydrogen phosphate ([tex]\(\text{HPO}_4^{2-}\)[/tex]).
Let's identify what gains or loses a proton:
- [tex]\(\text{H}_2\text{PO}_4^-\)[/tex] loses a proton (H⁺) to form [tex]\(\text{HPO}_4^{2-}\)[/tex]. Therefore, [tex]\(\text{H}_2\text{PO}_4^-\)[/tex] is acting as an acid, and [tex]\(\text{HPO}_4^{2-}\)[/tex] is its conjugate base.
- [tex]\(\text{H}_2\text{O}\)[/tex] gains a proton (H⁺) to form [tex]\(\text{H}_3\text{O}^+\)[/tex]. Thus, [tex]\(\text{H}_2\text{O}\)[/tex] is acting as a base, and [tex]\(\text{H}_3\text{O}^+\)[/tex] is its conjugate acid.
Considering the options provided:
1. [tex]\( \text{H}_2\text{O} \)[/tex] and [tex]\( \text{H}_3\text{O}^+ \)[/tex] form a conjugate base-acid pair.
2. [tex]\( \text{H}_2\text{O} \)[/tex] and [tex]\( \text{H}_2\text{PO}_4^- \)[/tex] do not form a conjugate pair.
3. [tex]\( \text{H}_2\text{PO}_4^- \)[/tex] and [tex]\( \text{HPO}_4^{2-} \)[/tex] form a conjugate acid-base pair.
4. [tex]\( \text{H}_2\text{PO}_4^- \)[/tex] and [tex]\( \text{H}_3\text{O}^+ \)[/tex] do not form a conjugate pair.
The correct pair that forms a base-conjugate acid pair in the given reaction is:
[tex]\[ \text{H}_2\text{PO}_4^- \text{ and } \text{HPO}_4^{2-} \][/tex]
Therefore, the answer is:
[tex]\[ \boxed{3} \][/tex]
- An acid loses a proton (H⁺) to form its conjugate base.
- A base gains a proton (H⁺) to form its conjugate acid.
Let's analyze the given reaction:
[tex]\[ \text{H}_2\text{PO}_4^- + \text{H}_2\text{O} \rightarrow \text{H}_3\text{O}^+ + \text{HPO}_4^{2-} \][/tex]
From this reaction:
- Di-hydrogen phosphate ([tex]\(\text{H}_2\text{PO}_4^-\)[/tex]) is reacting with water ([tex]\(\text{H}_2\text{O}\)[/tex]).
- The product formed includes hydronium ([tex]\(\text{H}_3\text{O}^+\)[/tex]) and hydrogen phosphate ([tex]\(\text{HPO}_4^{2-}\)[/tex]).
Let's identify what gains or loses a proton:
- [tex]\(\text{H}_2\text{PO}_4^-\)[/tex] loses a proton (H⁺) to form [tex]\(\text{HPO}_4^{2-}\)[/tex]. Therefore, [tex]\(\text{H}_2\text{PO}_4^-\)[/tex] is acting as an acid, and [tex]\(\text{HPO}_4^{2-}\)[/tex] is its conjugate base.
- [tex]\(\text{H}_2\text{O}\)[/tex] gains a proton (H⁺) to form [tex]\(\text{H}_3\text{O}^+\)[/tex]. Thus, [tex]\(\text{H}_2\text{O}\)[/tex] is acting as a base, and [tex]\(\text{H}_3\text{O}^+\)[/tex] is its conjugate acid.
Considering the options provided:
1. [tex]\( \text{H}_2\text{O} \)[/tex] and [tex]\( \text{H}_3\text{O}^+ \)[/tex] form a conjugate base-acid pair.
2. [tex]\( \text{H}_2\text{O} \)[/tex] and [tex]\( \text{H}_2\text{PO}_4^- \)[/tex] do not form a conjugate pair.
3. [tex]\( \text{H}_2\text{PO}_4^- \)[/tex] and [tex]\( \text{HPO}_4^{2-} \)[/tex] form a conjugate acid-base pair.
4. [tex]\( \text{H}_2\text{PO}_4^- \)[/tex] and [tex]\( \text{H}_3\text{O}^+ \)[/tex] do not form a conjugate pair.
The correct pair that forms a base-conjugate acid pair in the given reaction is:
[tex]\[ \text{H}_2\text{PO}_4^- \text{ and } \text{HPO}_4^{2-} \][/tex]
Therefore, the answer is:
[tex]\[ \boxed{3} \][/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.