Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Let's break down the solution step-by-step for each part of the problem.
### 1. Bill's Acceleration
1. Initial Velocity of Bill: [tex]\( u = 7 \, \text{m/s} \)[/tex]
2. Final Velocity of Bill: [tex]\( v = 19 \, \text{m/s} \)[/tex]
3. Time taken by Bill: [tex]\( t = 5 \, \text{seconds} \)[/tex]
The formula for acceleration ([tex]\( a \)[/tex]) is:
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{19 - 7}{5} \][/tex]
[tex]\[ a = \frac{12}{5} \][/tex]
[tex]\[ a = 2.4 \, \text{m/s}^2 \][/tex]
So, Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
### 2. Ben's Acceleration
1. Initial Velocity of Ben: [tex]\( u = 15 \, \text{m/s} \)[/tex]
2. Final Velocity of Ben: [tex]\( v = 21 \, \text{m/s} \)[/tex]
3. Time taken by Ben: [tex]\( t = 7 \, \text{seconds} \)[/tex]
Using the formula for acceleration ([tex]\( a \)[/tex]):
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{21 - 15}{7} \][/tex]
[tex]\[ a = \frac{6}{7} \][/tex]
[tex]\[ a \approx 0.8571 \, \text{m/s}^2 \][/tex]
So, Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
### 3. Faster Velocity
To determine who is traveling at a faster velocity, we compare the final velocities of Bill and Ben.
- Bill's final velocity: [tex]\( 19 \, \text{m/s} \)[/tex]
- Ben's final velocity: [tex]\( 21 \, \text{m/s} \)[/tex]
Ben's final velocity is higher than Bill's.
Therefore, Ben is traveling at a faster velocity.
### Summary
1. Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
2. Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
3. Ben is traveling at a faster velocity (21 m/s).
### 1. Bill's Acceleration
1. Initial Velocity of Bill: [tex]\( u = 7 \, \text{m/s} \)[/tex]
2. Final Velocity of Bill: [tex]\( v = 19 \, \text{m/s} \)[/tex]
3. Time taken by Bill: [tex]\( t = 5 \, \text{seconds} \)[/tex]
The formula for acceleration ([tex]\( a \)[/tex]) is:
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{19 - 7}{5} \][/tex]
[tex]\[ a = \frac{12}{5} \][/tex]
[tex]\[ a = 2.4 \, \text{m/s}^2 \][/tex]
So, Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
### 2. Ben's Acceleration
1. Initial Velocity of Ben: [tex]\( u = 15 \, \text{m/s} \)[/tex]
2. Final Velocity of Ben: [tex]\( v = 21 \, \text{m/s} \)[/tex]
3. Time taken by Ben: [tex]\( t = 7 \, \text{seconds} \)[/tex]
Using the formula for acceleration ([tex]\( a \)[/tex]):
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{21 - 15}{7} \][/tex]
[tex]\[ a = \frac{6}{7} \][/tex]
[tex]\[ a \approx 0.8571 \, \text{m/s}^2 \][/tex]
So, Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
### 3. Faster Velocity
To determine who is traveling at a faster velocity, we compare the final velocities of Bill and Ben.
- Bill's final velocity: [tex]\( 19 \, \text{m/s} \)[/tex]
- Ben's final velocity: [tex]\( 21 \, \text{m/s} \)[/tex]
Ben's final velocity is higher than Bill's.
Therefore, Ben is traveling at a faster velocity.
### Summary
1. Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
2. Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
3. Ben is traveling at a faster velocity (21 m/s).
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.