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2. A quadrilateral RSTU has vertices R(-11,7), S(1,5), T(9,-15), and U(1,-5). Find the distance between R(-11,7) and T(9,-15).

Sagot :

To find the distance between the points [tex]\( R(-11, 7) \)[/tex] and [tex]\( T(9, -15) \)[/tex], we need to use the distance formula. The distance formula for two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] in the coordinate plane is given by:

[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Let's identify our coordinates:
- For point [tex]\( R \)[/tex], [tex]\( x_1 = -11 \)[/tex] and [tex]\( y_1 = 7 \)[/tex]
- For point [tex]\( T \)[/tex], [tex]\( x_2 = 9 \)[/tex] and [tex]\( y_2 = -15 \)[/tex]

First, we calculate the differences in the x-coordinates and y-coordinates:

[tex]\[ \Delta x = x_2 - x_1 = 9 - (-11) = 9 + 11 = 20 \][/tex]
[tex]\[ \Delta y = y_2 - y_1 = -15 - 7 = -15 - 7 = -22 \][/tex]

Next, we plug these differences into the distance formula:

[tex]\[ d = \sqrt{(\Delta x)^2 + (\Delta y)^2} = \sqrt{(20)^2 + (-22)^2} \][/tex]

Let's compute the squares of these differences:

[tex]\[ (20)^2 = 400 \][/tex]
[tex]\[ (-22)^2 = 484 \][/tex]

Now, we add these squared differences:

[tex]\[ 400 + 484 = 884 \][/tex]

Finally, we take the square root of this sum to find the distance:

[tex]\[ d = \sqrt{884} \approx 29.732137494637012 \][/tex]

Therefore, the distance between the points [tex]\( R(-11, 7) \)[/tex] and [tex]\( T(9, -15) \)[/tex] is approximately [tex]\( 29.732 \)[/tex].