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Joanna bought the following amounts of fruit:

- [tex]\(1 \frac{1}{2}\)[/tex] pounds of apples
- [tex]\(\frac{3}{4}\)[/tex] of a pound of strawberries
- [tex]\(\frac{1}{2}\)[/tex] of a pound of grapes
- [tex]\(1 \frac{3}{4}\)[/tex] pounds of oranges
- [tex]\(1 \frac{1}{4}\)[/tex] pounds of pears

How many pounds of fruit did Joanna buy in all?

A. 5
B. [tex]\(5 \frac{3}{4}\)[/tex]
C. [tex]\(5 \frac{1}{2}\)[/tex]
D. [tex]\(5 \frac{1}{4}\)[/tex]


Sagot :

To determine the total pounds of fruit Joanna bought, we add up the individual pounds of each fruit.

1. Apples: [tex]\(1 \frac{1}{2}\)[/tex] pounds
- This can be converted into an improper fraction: [tex]\(1 \frac{1}{2} = \frac{3}{2}\)[/tex] pounds.
2. Strawberries: [tex]\(\frac{3}{4}\)[/tex] of a pound.
3. Grapes: [tex]\(\frac{1}{2}\)[/tex] of a pound.
- This can also be written as [tex]\(\frac{2}{4}\)[/tex] to facilitate addition.
4. Oranges: [tex]\(1 \frac{3}{4}\)[/tex] pounds.
- This converts to an improper fraction: [tex]\(1 \frac{3}{4} = \frac{7}{4}\)[/tex] pounds.
5. Pears: [tex]\(1 \frac{1}{4}\)[/tex] pounds.
- This converts to an improper fraction: [tex]\(1 \frac{1}{4} = \frac{5}{4}\)[/tex] pounds.

Next, convert all amounts to either mixed fractions or improper fractions as necessary and sum them up:

[tex]\[ \begin{align*} \text{Apples} &: \frac{3}{2} = \frac{6}{4} \\ \text{Strawberries} &: \frac{3}{4} \\ \text{Grapes} &: \frac{2}{4} \\ \text{Oranges} &: \frac{7}{4} \\ \text{Pears} &: \frac{5}{4} \end{align*} \][/tex]

Combine all fractions over the common denominator 4:

[tex]\[ \frac{6}{4} + \frac{3}{4} + \frac{2}{4} + \frac{7}{4} + \frac{5}{4} = \frac{23}{4} \][/tex]

Convert back to a mixed number:

[tex]\[ \frac{23}{4} = 5 \frac{3}{4} \][/tex]

Thus, the total pounds of fruit Joanna bought is [tex]\(5 \frac{3}{4}\)[/tex] pounds.

So, the correct answer is:
B. [tex]\(5 \frac{3}{4}\)[/tex]