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What is the solution to the equation below? Round your answer to two decimal places.

10 * log(4x) = 25

A. x = 316.23
B. x = 79.06
C. x = 1264.91
D. x = 93.78

Sagot :

To solve the equation [tex]\( 10 \cdot \log(4x) = 25 \)[/tex], follow these steps:

1. Isolate the logarithmic expression.
[tex]\[ 10 \cdot \log(4x) = 25 \][/tex]
Divide both sides by 10:
[tex]\[ \log(4x) = \frac{25}{10} = 2.5 \][/tex]

2. Rewrite the equation in exponential form.
The equation [tex]\(\log(4x) = 2.5\)[/tex] can be written in exponential form as:
[tex]\[ 4x = 10^{2.5} \][/tex]

3. Calculate the numeric value of [tex]\(10^{2.5}\)[/tex].

[tex]\(10^{2.5}\)[/tex] approximately equals 316.23.

4. Solve for [tex]\(x\)[/tex].
Divide both sides of the equation [tex]\(4x = 316.23\)[/tex] by 4:
[tex]\[ x = \frac{316.23}{4} \approx 79.06 \][/tex]

Hence, the solution to the equation [tex]\(10 \cdot \log(4x) = 25\)[/tex] rounded to two decimal places is:

[tex]\[ \boxed{x = 79.06} \][/tex]

Therefore, the correct answer is:
B. [tex]\( x = 79.06 \)[/tex]