Let's approach the given table and the operations step by step to arrive to the correct numerical solution.
[tex]\[
\begin{array}{|c|c|c|c|}
\hline
x & 3 & - & 7 \\
\hline
5 & 2 & 27 & \div \\
\hline
1 & 8 & + & 2 \\
\hline
\end{array}
\][/tex]
First, identify and label the variables given in the table:
- [tex]\( x = 3 \)[/tex]
- [tex]\( y = 5 \)[/tex]
- [tex]\( z = 7 \)[/tex]
With these variables in mind, let's form the expression involving these variables.
The task is to compute a result using these values and an arithmetic expression involving multiplication and subtraction.
Given that:
- [tex]\( y = 5 \)[/tex]
- [tex]\( z = 7 \)[/tex]
- [tex]\( x = 3 \)[/tex]
Let's consider the expression combining multiplication and subtraction:
[tex]\[ y \times z - x \][/tex]
Now substitute the values of [tex]\( y \)[/tex], [tex]\( z \)[/tex], and [tex]\( x \)[/tex] into the expression:
[tex]\[ 5 \times 7 - 3 \][/tex]
From here, simplify the expression step by step:
1. First, perform the multiplication:
[tex]\[ 5 \times 7 = 35 \][/tex]
2. Next, subtract [tex]\( x \)[/tex]:
[tex]\[ 35 - 3 = 32 \][/tex]
Thus, the final result of the calculation is:
[tex]\[ 32 \][/tex]
