Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine the energy generated from freezing [tex]\(2.5 \text{ g}\)[/tex] of water, you need to follow these steps:
1. Determine the number of moles of water:
- Given the mass of water [tex]\(2.5 \text{ g}\)[/tex] and its molar mass [tex]\(18.02 \text{ g/mol}\)[/tex], calculate the number of moles using the formula:
[tex]\[ \text{moles of water} = \frac{\text{mass of water}}{\text{molar mass}} \][/tex]
Plugging in the values:
[tex]\[ \text{moles of water} = \frac{2.5 \text{ g}}{18.02 \text{ g/mol}} \approx 0.1387 \text{ mol} \][/tex]
2. Calculate the energy generated from freezing:
- The enthalpy change for the phase transition from liquid to solid (freezing point) is known as the enthalpy of fusion ([tex]\(\Delta H_{\text{fusion}}\)[/tex]), which is given as [tex]\(6.03 \text{ kJ/mol}\)[/tex].
- The energy generated can be calculated by multiplying the number of moles of water by the enthalpy of fusion:
[tex]\[ \text{energy generated} = \text{moles of water} \times \Delta H_{\text{fusion}} \][/tex]
Plugging in the values:
[tex]\[ \text{energy generated} = 0.1387 \text{ mol} \times 6.03 \text{ kJ/mol} \approx 0.8366 \text{ kJ} \][/tex]
Therefore, the correct option is:
B. [tex]\(2.5 \text{ g} \times \frac{1 \text{ mol}}{18.02 \text{ g}} \times 6.03 \text{ kJ/mol}\)[/tex]
1. Determine the number of moles of water:
- Given the mass of water [tex]\(2.5 \text{ g}\)[/tex] and its molar mass [tex]\(18.02 \text{ g/mol}\)[/tex], calculate the number of moles using the formula:
[tex]\[ \text{moles of water} = \frac{\text{mass of water}}{\text{molar mass}} \][/tex]
Plugging in the values:
[tex]\[ \text{moles of water} = \frac{2.5 \text{ g}}{18.02 \text{ g/mol}} \approx 0.1387 \text{ mol} \][/tex]
2. Calculate the energy generated from freezing:
- The enthalpy change for the phase transition from liquid to solid (freezing point) is known as the enthalpy of fusion ([tex]\(\Delta H_{\text{fusion}}\)[/tex]), which is given as [tex]\(6.03 \text{ kJ/mol}\)[/tex].
- The energy generated can be calculated by multiplying the number of moles of water by the enthalpy of fusion:
[tex]\[ \text{energy generated} = \text{moles of water} \times \Delta H_{\text{fusion}} \][/tex]
Plugging in the values:
[tex]\[ \text{energy generated} = 0.1387 \text{ mol} \times 6.03 \text{ kJ/mol} \approx 0.8366 \text{ kJ} \][/tex]
Therefore, the correct option is:
B. [tex]\(2.5 \text{ g} \times \frac{1 \text{ mol}}{18.02 \text{ g}} \times 6.03 \text{ kJ/mol}\)[/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.