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Sagot :
Answer: b=2−p2b=22−p.
Step-by-step explanation: To solve for ll in the equation p=2(1−b)p=2(1−b):
First, distribute the 2 to both terms inside the parentheses:
p=2−2bp=2−2b
Next, add 2b to both sides of the equation to isolate the variable term:
p+2b=2p+2b=2
Now, subtract pp from both sides to isolate the constant term:
2b=2−p2b=2−p
Finally, divide both sides by 2 to solve for bb:
b=2−p2b=22−p
So, b=2−p2b=22−p.
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