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Select the correct row in the table.

Which row reveals the [tex]$x$[/tex]-intercept of function [tex]$f$[/tex]?
[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $f(x)$ \\
\hline
-6 & 4 \\
\hline
-4 & 0 \\
\hline
-2 & -4 \\
\hline
0 & -16 \\
\hline
1 & -25 \\
\hline
\end{tabular}
\][/tex]


Sagot :

To determine the [tex]\( x \)[/tex]-intercept of the function [tex]\( f \)[/tex], we need to identify the [tex]\( x \)[/tex]-value for which the function [tex]\( f(x) \)[/tex] equals zero. This means we are looking for a row in the table where the value of [tex]\( f(x) \)[/tex] is 0.

Let's examine each row in the given table:

[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -6 & 4 \\ \hline -4 & 0 \\ \hline -2 & -4 \\ \hline 0 & -16 \\ \hline 1 & -25 \\ \hline \end{array} \][/tex]

1. For [tex]\( x = -6 \)[/tex], [tex]\( f(x) = 4 \)[/tex] (not zero).
2. For [tex]\( x = -4 \)[/tex], [tex]\( f(x) = 0 \)[/tex] (this is zero).
3. For [tex]\( x = -2 \)[/tex], [tex]\( f(x) = -4 \)[/tex] (not zero).
4. For [tex]\( x = 0 \)[/tex], [tex]\( f(x) = -16 \)[/tex] (not zero).
5. For [tex]\( x = 1 \)[/tex], [tex]\( f(x) = -25 \)[/tex] (not zero).

From this analysis, we see that the row where [tex]\( f(x) \)[/tex] equals zero is:

[tex]\[ x = -4 \][/tex]

Therefore, the correct row in the table that reveals the [tex]\( x \)[/tex]-intercept of the function [tex]\( f \)[/tex] is:

[tex]\[ (-4, 0) \][/tex]

So, the [tex]\( x \)[/tex]-intercept of the function [tex]\( f \)[/tex] is [tex]\( x = -4 \)[/tex].