Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Which system of equations can be graphed to find the solution(s) to [tex]\( 4x^2 = x^2 + 7 \)[/tex]?

A.
[tex]\[
\begin{cases}
y = 3x^2 \\
y = x^2 + 7
\end{cases}
\][/tex]

B.
[tex]\[
\begin{cases}
y = 3x^2 + 7 \\
y = x^2 + 7
\end{cases}
\][/tex]

C.
[tex]\[
\begin{cases}
y = 4x^2 \\
y = x^2 + 7
\end{cases}
\][/tex]

D.
[tex]\[
\begin{cases}
y = 4x^2 \\
y = 4x^2 + 7
\end{cases}
\][/tex]

Sagot :

To identify which system of equations can be graphed to find the solution(s) to [tex]\(4x^2 = x^2 + 7\)[/tex], we need to follow these steps:

1. Rearrange the given equation:
[tex]\[ 4x^2 = x^2 + 7 \][/tex]
By rearranging, we subtract [tex]\(x^2\)[/tex] from both sides:
[tex]\[ 4x^2 - x^2 = 7 \][/tex]
This simplifies to:
[tex]\[ 3x^2 = 7 \][/tex]

2. Express the given equation as two separate equations:
We can rewrite the rearranged equation [tex]\(3x^2 = 7\)[/tex] using function notation. Essentially, we want two functions [tex]\(y\)[/tex] which form the equality:
[tex]\[ y = 4x^2 \quad \text{and} \quad y = x^2 + 7 \][/tex]

3. Select the correct system of equations:
Looking at the systems provided, we compare:

- [tex]\(\left\{\begin{array}{l}y = 3x^2 \\ y = x^2 + 7\end{array}\right.\)[/tex]
- [tex]\(\left\{\begin{array}{l}y = 3x^2 + 7 \\ y = x^2 + 7\end{array}\right.\)[/tex]
- [tex]\(\left\{\begin{array}{l}y = 4x^2 \\ y = x^2 + 7\end{array}\right.\)[/tex]
- [tex]\(\left\{\begin{array}{l}y = 4x^2 \\ y = 4x^2 + 7\end{array}\right.\)[/tex]

The system that matches [tex]\(y = 4x^2\)[/tex] and [tex]\(y = x^2 + 7\)[/tex] is:
[tex]\[ \left\{\begin{array}{l} y = 4x^2 \\ y = x^2 + 7 \end{array}\right. \][/tex]

Thus, the system of equations that can be graphed to find the solution to [tex]\(4x^2 = x^2 + 7\)[/tex] is:

[tex]\(\boxed{\left\{\begin{array}{l}y=4 x^2 \\ y=x^2+7\end{array}\right.}\)[/tex]