Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

The table shows how far a distance runner has traveled since the race began. What is her average rate of change, in miles per hour, during the interval 0.75 to 1.00 hours?

\begin{tabular}{|c|c|}
\hline
Time Elapsed (Hours) & Miles Traveled (Miles) \\
\hline
0.50 & 2.00 \\
\hline
0.75 & 3.50 \\
\hline
1.00 & 4.75 \\
\hline
\end{tabular}

A. 4.75 miles per hour
B. 5.00 miles per hour
C. 5.50 miles per hour
D. 6.00 miles per hour


Sagot :

To find the average rate of change in miles per hour during the interval from 0.75 to 1.00 hours for the distance runner, follow these steps:

1. Identify the initial and final times within the given interval:
[tex]\[ \text{Initial Time ( \( t_{\text{initial}} \) )} = 0.75 \text{ hours} \][/tex]
[tex]\[ \text{Final Time ( \( t_{\text{final}} \) )} = 1.00 \text{ hours} \][/tex]

2. Identify the distance (miles) traveled at these corresponding times:
[tex]\[ \text{Miles at \( t_{\text{initial}} \) } = 3.50 \text{ miles} \][/tex]
[tex]\[ \text{Miles at \( t_{\text{final}} \) } = 4.75 \text{ miles} \][/tex]

3. Calculate the change in distance ([tex]\( \Delta \text{Miles} \)[/tex]):
[tex]\[ \Delta \text{Miles} = \text{Miles at \( t_{\text{final}} \)} - \text{Miles at \( t_{\text{initial}} \)} \][/tex]
[tex]\[ \Delta \text{Miles} = 4.75 \text{ miles} - 3.50 \text{ miles} = 1.25 \text{ miles} \][/tex]

4. Calculate the change in time ([tex]\( \Delta \text{Time} \)[/tex]):
[tex]\[ \Delta \text{Time} = t_{\text{final}} - t_{\text{initial}} \][/tex]
[tex]\[ \Delta \text{Time} = 1.00 \text{ hours} - 0.75 \text{ hours} = 0.25 \text{ hours} \][/tex]

5. Determine the average rate of change (miles per hour) by dividing the change in distance by the change in time:
[tex]\[ \text{Average Rate of Change} = \frac{\Delta \text{Miles}}{\Delta \text{Time}} \][/tex]
[tex]\[ \frac{1.25 \text{ miles}}{0.25 \text{ hours}} = 5.0 \text{ miles per hour} \][/tex]

So, the average rate of change for the distance runner during the interval from 0.75 to 1.00 hours is:
[tex]\(\boxed{5.0 \text{ miles per hour}}\)[/tex]