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The temperature is [tex]\( 60^{\circ} F \)[/tex]. The temperature will decrease by [tex]\( 3^{\circ} F \)[/tex] each hour. Let [tex]\( h \)[/tex] be the number of hours.

When will the temperature be below [tex]\( 32^{\circ} F \)[/tex]?

Write an inequality for this problem.

A. [tex]\( 60 - 3h \leq 32 \)[/tex]
B. [tex]\( 60 + 3h \ \textless \ 32 \)[/tex]
C. [tex]\( 60 - 3h \ \textless \ 32 \)[/tex]
D. [tex]\( 60 + 3h \leq 32 \)[/tex]


Sagot :

To determine when the temperature will be below [tex]$32^{\circ} F$[/tex] given that it starts at [tex]$60^{\circ} F$[/tex] and decreases by [tex]$3^{\circ} F$[/tex] each hour, we need to set up an inequality.

1. Start with the initial temperature, which is [tex]$60^{\circ} F$[/tex].

2. The temperature decreases by [tex]$3^{\circ} F$[/tex] each hour. After [tex]$h$[/tex] hours, the temperature will be reduced by [tex]$3h$[/tex] degrees. So, the temperature after [tex]$h$[/tex] hours can be described by the expression [tex]$60 - 3h$[/tex].

3. We want to find when this resulting temperature is below [tex]$32^{\circ} F$[/tex]. Therefore, we need to set up the inequality:
[tex]\[ 60 - 3h < 32 \][/tex]

4. This inequality will allow us to solve for the number of hours, [tex]$h$[/tex], after which the temperature will be below [tex]$32^{\circ} F$[/tex].

So, the correct inequality for this problem is:
[tex]\[ 60 - 3h < 32 \][/tex]

The correct answer is:
[tex]\[ \boxed{C. \ 60 - 3h < 32} \][/tex]