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Becca graphs the equations [tex]\( y = -3(x - 1) \)[/tex] and [tex]\( y = x - 5 \)[/tex] to solve the equation [tex]\( -3(x - 1) = x - 5 \)[/tex].

What are the solution(s) of [tex]\( -3(x - 1) = x - 5 \)[/tex]?

A. [tex]\(-5\)[/tex]
B. [tex]\(3\)[/tex]


Sagot :

To solve the equation [tex]\(-3(x-1)=x-5\)[/tex], we can follow these steps:

### Step-by-Step Solution:

1. Distribute the -3 on the left side:
[tex]\[ -3(x-1) = x - 5 \][/tex]
Apply the distributive property to the left side:
[tex]\[ -3x + 3 = x - 5 \][/tex]

2. Combine like terms:
Bring all terms involving [tex]\(x\)[/tex] to one side of the equation and constants to the other side. To do this, add [tex]\(3x\)[/tex] to both sides:
[tex]\[ -3x + 3 + 3x = x - 5 + 3x \][/tex]
Simplify:
[tex]\[ 3 = 4x - 5 \][/tex]

3. Isolate the [tex]\(x\)[/tex] term:
Add 5 to both sides to get the constant term on the right side:
[tex]\[ 3 + 5 = 4x - 5 + 5 \][/tex]
Simplify:
[tex]\[ 8 = 4x \][/tex]

4. Solve for [tex]\(x\)[/tex]:
Divide both sides by 4:
[tex]\[ \frac{8}{4} = \frac{4x}{4} \][/tex]
Simplify:
[tex]\[ x = 2 \][/tex]

### Verification:

To ensure no mistakes were made, substitute [tex]\(x = 2\)[/tex] back into the original equation [tex]\(y = -3(x-1)\)[/tex] and [tex]\(y = x-5\)[/tex]:

1. First equation [tex]\(y = -3(x - 1)\)[/tex]:
[tex]\[ y = -3(2 - 1) = -3(1) = -3 \][/tex]
2. Second equation [tex]\(y = x - 5\)[/tex]:
[tex]\[ y = 2 - 5 = -3 \][/tex]

Since both equations yield [tex]\(y = -3\)[/tex] when [tex]\(x = 2\)[/tex], the solution satisfies both equations. Therefore, there are no additional solutions.

### Conclusion:
The solution to the equation [tex]\(-3(x-1)=x-5\)[/tex] is:
[tex]\[ x = 2 \][/tex]

There are no other solutions. Thus, the final answer is:

[tex]\[ \boxed{2} \][/tex]
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