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ross is comparing a square root of 11 and 5.4 with a 4 repeating. he says the a spuare root of 11 is greater then 5.4 repeating because a square root of 11 = 5.5 is he correct

Sagot :

Answer:

Step-by-step explanation: Ross's reasoning is incorrect. Let's clarify the comparison step by step:

   Square Root of 11: Approximate value is 11≈3.316611

   ​≈3.3166.

   5.4 with 4 repeating: This can be expressed as 5.4444…5.4444….

Ross's statement:

   Ross claims that 11=5.511

   ​=5.5.

This statement is incorrect. 1111

​ is approximately 3.31663.3166, not 5.55.5.

Now, let's compare 1111

​ and 5.4444…5.4444…:

   11≈3.316611

   ​≈3.3166

   5.4444…5.4444… is a repeating decimal, which equals 499949​.

To determine which is greater:

   11≈3.316611

   ​≈3.3166

   5.4444…=499≈5.44445.4444…=949​≈5.4444

Clearly, 5.4444…5.4444… (which equals 499949​) is greater than 11≈3.316611

​≈3.3166.

Therefore, Ross is incorrect in stating that 11=5.511

​=5.5. In fact, 1111

​ is less than 5.4444…5.4444…. The correct comparison is 5.4444…>115.4444…>11

​.

So, Ross's reasoning is not correct based on the actual values of 1111

​ and 5.4444…5.4444….

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