Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To determine the average rate at which the object falls during the first 3 seconds, we need to find the change in height over the change in time. This can be achieved by calculating the difference in height at [tex]\( t = 3 \)[/tex] seconds and [tex]\( t = 0 \)[/tex] seconds, and then dividing by the time interval, which is 3 seconds.
Given the height function:
[tex]\[ h(t) = 300 - 16t^2 \][/tex]
1. Calculate [tex]\( h(3) \)[/tex]:
[tex]\[ h(3) = 300 - 16(3)^2 = 300 - 144 = 156 \][/tex]
2. Calculate [tex]\( h(0) \)[/tex]:
[tex]\[ h(0) = 300 - 16(0)^2 = 300 \][/tex]
3. Determine the change in height over the 3-second interval:
[tex]\[ h(3) - h(0) = 156 - 300 = -144 \][/tex]
4. Divide the change in height by the time interval to find the average rate of fall:
[tex]\[ \frac{h(3) - h(0)}{3} = \frac{-144}{3} = -48 \][/tex]
Thus, the expression [tex]\(\frac{h(3) - h(0)}{3}\)[/tex] correctly determines the average rate at which the object falls during the first 3 seconds of its fall. Therefore, the answer is:
[tex]\[ \boxed{\frac{h(3) - h(0)}{3}} \][/tex]
Given the height function:
[tex]\[ h(t) = 300 - 16t^2 \][/tex]
1. Calculate [tex]\( h(3) \)[/tex]:
[tex]\[ h(3) = 300 - 16(3)^2 = 300 - 144 = 156 \][/tex]
2. Calculate [tex]\( h(0) \)[/tex]:
[tex]\[ h(0) = 300 - 16(0)^2 = 300 \][/tex]
3. Determine the change in height over the 3-second interval:
[tex]\[ h(3) - h(0) = 156 - 300 = -144 \][/tex]
4. Divide the change in height by the time interval to find the average rate of fall:
[tex]\[ \frac{h(3) - h(0)}{3} = \frac{-144}{3} = -48 \][/tex]
Thus, the expression [tex]\(\frac{h(3) - h(0)}{3}\)[/tex] correctly determines the average rate at which the object falls during the first 3 seconds of its fall. Therefore, the answer is:
[tex]\[ \boxed{\frac{h(3) - h(0)}{3}} \][/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.