Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

The height, [tex]\( h \)[/tex], of a falling object [tex]\( t \)[/tex] seconds after it is dropped from a platform 300 feet above the ground is modeled by the function [tex]\( h(t) = 300 - 16t^2 \)[/tex].

Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall?

A. [tex]\( h(3) - h(0) \)[/tex]
B. [tex]\( h\left(\frac{3}{3}\right) - h\left(\frac{0}{3}\right) \)[/tex]
C. [tex]\( \frac{h(3)}{3} \)[/tex]
D. [tex]\( \frac{h(3) - h(0)}{3} \)[/tex]

Sagot :

To determine the average rate at which the object falls during the first 3 seconds, we need to find the change in height over the change in time. This can be achieved by calculating the difference in height at [tex]\( t = 3 \)[/tex] seconds and [tex]\( t = 0 \)[/tex] seconds, and then dividing by the time interval, which is 3 seconds.

Given the height function:
[tex]\[ h(t) = 300 - 16t^2 \][/tex]

1. Calculate [tex]\( h(3) \)[/tex]:
[tex]\[ h(3) = 300 - 16(3)^2 = 300 - 144 = 156 \][/tex]

2. Calculate [tex]\( h(0) \)[/tex]:
[tex]\[ h(0) = 300 - 16(0)^2 = 300 \][/tex]

3. Determine the change in height over the 3-second interval:
[tex]\[ h(3) - h(0) = 156 - 300 = -144 \][/tex]

4. Divide the change in height by the time interval to find the average rate of fall:
[tex]\[ \frac{h(3) - h(0)}{3} = \frac{-144}{3} = -48 \][/tex]

Thus, the expression [tex]\(\frac{h(3) - h(0)}{3}\)[/tex] correctly determines the average rate at which the object falls during the first 3 seconds of its fall. Therefore, the answer is:

[tex]\[ \boxed{\frac{h(3) - h(0)}{3}} \][/tex]