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What is the molar concentration of a solution with a volume of 1.5 L containing 660 g of [tex]\( Ca_3(PO_4)_2 \)[/tex]?

Given:
- Molar mass of [tex]\( Ca_3(PO_4)_2 \)[/tex]: 310.18 g/mol

Calculate:
[tex]\[ \text{Concentration} = \frac{? \, \text{mol}}{L} \][/tex]


Sagot :

To determine the molar concentration of a solution with a given volume and mass of solute, we can follow these steps:

### Step 1: Determine the number of moles of the solute (Ca₃(PO₄)₂)

First, we need to convert the mass of the solute from grams to moles. This conversion uses the molar mass of the solute.

Given:
- Mass of solute (Ca₃(PO₄)₂) = 660 g
- Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol

To find the number of moles ([tex]\(n\)[/tex]):
[tex]\[ n = \frac{\text{mass of solute}}{\text{molar mass}} \][/tex]
[tex]\[ n = \frac{660 \, \text{g}}{310.18 \, \text{g/mol}} \][/tex]
[tex]\[ n \approx 2.1278 \, \text{moles} \][/tex]

### Step 2: Calculate the molar concentration

Next, we use the volume of the solution to find the molar concentration. Molar concentration (M) is defined as the number of moles of solute per liter of solution.

Given:
- Volume of the solution = 1.5 L

To find the molar concentration ([tex]\(C\)[/tex]):
[tex]\[ C = \frac{\text{number of moles of solute}}{\text{volume of solution}} \][/tex]
[tex]\[ C = \frac{2.1278 \, \text{moles}}{1.5 \, \text{L}} \][/tex]
[tex]\[ C \approx 1.4185 \, \text{mol/L} \][/tex]

### Conclusion

The molar concentration of the solution is approximately [tex]\( 1.4185 \, \text{mol/L} \)[/tex].