Mary needs a 0.02 M solution of NaNO3. She calculates that she needs 2.00 g of NaNO3 for 0.02 mol. She puts this solid into a 1.00 L volumetric flask and fills the flask to the 1.00 L mark.

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12-06-2024
Chemistry

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Mary needs a 0.02 M solution of NaNO3. She calculates that she needs 2.00 g of NaNO3 for 0.02 mol. She puts this solid into a 1.00 L volumetric flask and fills the flask to the 1.00 L mark.

Sagot :

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