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Brigid is picking strawberries at the Pick-Your-Own Farm. Her goal is to pick 5 bushels of strawberries. She has already picked [tex]\(1 \frac{1}{2}\)[/tex] bushels, and she picks at a rate of [tex]\(\frac{5}{8}\)[/tex] bushel per hour. The scenario is represented as [tex]\(\frac{5}{8} h + 1 \frac{1}{2} = 5\)[/tex], where [tex]\(h\)[/tex] is the number of hours she picks.

How many more hours will it take Brigid to fill 5 bushels of strawberries?

A. [tex]\(2 \frac{3}{16}\)[/tex] hours
B. [tex]\(4 \frac{1}{16}\)[/tex] hours
C. [tex]\(5 \frac{3}{5}\)[/tex] hours
D. [tex]\(10 \frac{2}{5}\)[/tex] hours


Sagot :

Let's solve this step-by-step.

The given scenario can be represented by the equation:
[tex]\[ \frac{5}{8} h + 1 \frac{1}{2} = 5 \][/tex]

First, let's simplify [tex]\(1 \frac{1}{2}\)[/tex]:

[tex]\[ 1 \frac{1}{2} = 1 + \frac{1}{2} = \frac{2}{2} + \frac{1}{2} = \frac{3}{2} \][/tex]

Now, the equation becomes:
[tex]\[ \frac{5}{8} h + \frac{3}{2} = 5 \][/tex]

Next, isolate [tex]\( h \)[/tex] by subtracting [tex]\(\frac{3}{2}\)[/tex] from both sides:

[tex]\[ \frac{5}{8} h = 5 - \frac{3}{2} \][/tex]

To perform the subtraction, convert 5 to a fraction with a common denominator of 2:

[tex]\[ 5 = \frac{10}{2} \][/tex]

So,

[tex]\[ 5 - \frac{3}{2} = \frac{10}{2} - \frac{3}{2} = \frac{7}{2} \][/tex]

Now our equation is:

[tex]\[ \frac{5}{8} h = \frac{7}{2} \][/tex]

To solve for [tex]\(h\)[/tex], multiply both sides by the reciprocal of [tex]\(\frac{5}{8}\)[/tex], which is [tex]\(\frac{8}{5}\)[/tex]:

[tex]\[ h = \frac{7}{2} \times \frac{8}{5} \][/tex]

Multiply the numerators and the denominators:

[tex]\[ h = \frac{7 \times 8}{2 \times 5} = \frac{56}{10} = 5.6 \][/tex]

Convert 5.6 into a mixed number:

[tex]\[ 5.6 = 5 \frac{3}{5} \][/tex]

Thus, we have:
- Brigid has 3.5 bushels remaining to pick.
- She needs 5.6 hours, which is [tex]\(5 \frac{3}{5} \)[/tex] hours.

Therefore, the correct answer is [tex]\( 5 \frac{3}{5} \)[/tex] hours, written as [tex]\(5 \frac{3}{5}\)[/tex]. This matches the option [tex]\(5 \frac{3}{5}\)[/tex].

So the answer is:

[tex]\[ \boxed{5 \frac{3}{5}} \][/tex]