Post-Laboratory Question:

1. What is the equation for the dehydration of [tex]$ CuSO_4 \cdot 5H_2O $[/tex]?

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12-06-2024
Chemistry

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Post-Laboratory Question:

1. What is the equation for the dehydration of [tex]$ CuSO_4 \cdot 5H_2O $[/tex]?

Sagot :

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GinnyAnswer GinnyAnswer · Answer 1 · 2024-06-12T23:15:59-04:00

Sure, I can help with that.

The dehydration of copper(II) sulfate pentahydrate ([tex]$CuSO_4 \cdot 5H_2O$[/tex]) involves the removal of water molecules from the hydrated compound. This process results in anhydrous copper(II) sulfate ([tex]$CuSO_4$[/tex]) and water ([tex]$H_2O$[/tex]). The balanced chemical equation for this reaction is:

[tex]\[ \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \rightarrow \text{CuSO}_4 + 5\text{H}_2\text{O} \][/tex]

Here’s a breakdown of the equation:
- [tex]$CuSO_4 \cdot 5H_2O$[/tex]: Copper(II) sulfate pentahydrate, which is the hydrated form of copper(II) sulfate.
- [tex]$CuSO_4$[/tex]: Anhydrous copper(II) sulfate, which means it no longer has water molecules attached.
- [tex]$5H_2O$[/tex]: Five molecules of water are released during the dehydration process.

So, the molecule of copper(II) sulfate pentahydrate releases five water molecules when it is dehydrated, resulting in anhydrous copper(II) sulfate.

Post-Laboratory Question:

1. What is the equation for the dehydration of [tex]\( CuSO_4 \cdot 5H_2O \)[/tex]?

Sagot :

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