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Post-Laboratory Question:

1. What is the equation for the dehydration of [tex]\( CuSO_4 \cdot 5H_2O \)[/tex]?

Sagot :

GinnyAnswer
Sure, I can help with that.

The dehydration of copper(II) sulfate pentahydrate ([tex]$CuSO_4 \cdot 5H_2O$[/tex]) involves the removal of water molecules from the hydrated compound. This process results in anhydrous copper(II) sulfate ([tex]$CuSO_4$[/tex]) and water ([tex]$H_2O$[/tex]). The balanced chemical equation for this reaction is:

[tex]\[ \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \rightarrow \text{CuSO}_4 + 5\text{H}_2\text{O} \][/tex]

Here’s a breakdown of the equation:
- [tex]$CuSO_4 \cdot 5H_2O$[/tex]: Copper(II) sulfate pentahydrate, which is the hydrated form of copper(II) sulfate.
- [tex]$CuSO_4$[/tex]: Anhydrous copper(II) sulfate, which means it no longer has water molecules attached.
- [tex]$5H_2O$[/tex]: Five molecules of water are released during the dehydration process.

So, the molecule of copper(II) sulfate pentahydrate releases five water molecules when it is dehydrated, resulting in anhydrous copper(II) sulfate.
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