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A jetliner uses 3,600 gallons of fuel per hour while cruising. The jetliner has 15,000 gallons of fuel in its tank when it begins to cruise.

If [tex]\( y \)[/tex] represents the amount of fuel, in thousands of gallons, remaining in the fuel tank after the jetliner cruises for [tex]\( x \)[/tex] hours, determine the graph of the solution set and the equation modeled by the graph.

[tex]\[
\begin{tabular}{|c|c|}
\hline
A. \( y = (15 - 3.6) - x \) & B. \( y = 15x - 3.6 \) \\
\hline
C. \( y = 15 - 3.6x \) & D. \( y = (15 - 3.6)x \) \\
\hline
\end{tabular}
\][/tex]


Sagot :

To determine the graph of the solution set for this situation and the equation modeled by the graph, follow these steps:

1. Identify the initial amount of fuel:
The jetliner starts with 15,000 gallons of fuel in its tank.

2. Determine the fuel usage rate:
The jetliner uses 3,600 gallons of fuel per hour.

3. Define the variables:
Let [tex]\( x \)[/tex] represent the number of hours the jetliner has been cruising.
Let [tex]\( y \)[/tex] represent the amount of fuel remaining in the tank in thousands of gallons.

4. Write the equation for the remaining fuel in gallons:
The remaining fuel after [tex]\( x \)[/tex] hours can be calculated by subtracting the total fuel used from the initial amount:
[tex]\[ \text{Remaining fuel in gallons} = 15000 - 3600x \][/tex]

5. Convert the remaining fuel to thousands of gallons:
Since [tex]\( y \)[/tex] represents the remaining fuel in thousands of gallons, divide the remaining fuel by 1,000:
[tex]\[ y = \frac{15000 - 3600x}{1000} \][/tex]

6. Simplify the equation:
Divide the numerator by 1,000:
[tex]\[ y = 15 - 3.6x \][/tex]

Therefore, the equation that models the graph for the remaining fuel in the jetliner's tank in thousands of gallons after [tex]\( x \)[/tex] hours of cruising is:
[tex]\[ y = 15 - 3.6x \][/tex]

Among the given options, the correct equation is:
[tex]\[ y = 15 - 3.6x \][/tex]