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Tia lives at the corner of 4th Street and 8th Avenue. Lei lives at the corner of 12th Street and 20th Avenue. The fruit market is [tex]$\frac{3}{4}$[/tex] the distance from Tia's home to Lei's home.

Where is the fruit market?

A. 6th Street and 11th Avenue
B. 10th Street and 17th Avenue
C. 9th Street and 15th Avenue
D. 8th Street and 14th Avenue

Sagot :

Alright! Let's solve this step-by-step.

First, we identify the coordinates of Tia's and Lei's homes:
- Tia lives at the corner of 4th Street and 8th Avenue, so her home is at [tex]\((x_1, y_1) = (4, 8)\)[/tex].
- Lei lives at the corner of 12th Street and 20th Avenue, so his home is at [tex]\((x_2, y_2) = (12, 20)\)[/tex].

The fruit market is [tex]\(\frac{3}{4}\)[/tex] the distance from Tia's home to Lei's home.

We are given the formulas to find the coordinates [tex]\((x, y)\)[/tex] where the fruit market is located:

[tex]\[ x=\left(\frac{m}{m+n}\right)\left(x_2-x_1\right)+x_1 \][/tex]

[tex]\[ y=\left(\frac{m}{m+n}\right)\left(y_2-y_1\right)+y_1 \][/tex]

Here, [tex]\(m = 3\)[/tex] and [tex]\(n = 1\)[/tex].

Let's find the [tex]\(x\)[/tex] coordinate first:
[tex]\[ (x_2 - x_1) = 12 - 4 = 8 \][/tex]

[tex]\[ \left( \frac{m}{m+n} \right) = \left( \frac{3}{3+1} \right) = \left( \frac{3}{4} \right) \][/tex]

[tex]\[ x= \left( \frac{3}{4} \right) \left(8\right) + 4 = 6 + 4 = 10 \][/tex]

So, the [tex]\(x\)[/tex] coordinate is [tex]\(10\)[/tex].

Now, let's find the [tex]\(y\)[/tex] coordinate:
[tex]\[ (y_2 - y_1) = 20 - 8 = 12 \][/tex]

[tex]\[ \left( \frac{m}{m+n} \right) = \left( \frac{3}{3+1} \right) = \left( \frac{3}{4} \right) \][/tex]

[tex]\[ y= \left( \frac{3}{4} \right) \left(12\right) + 8 = 9 + 8 = 17 \][/tex]

So, the [tex]\(y\)[/tex] coordinate is [tex]\(17\)[/tex].

Thus, the coordinates of the fruit market are [tex]\((10, 17)\)[/tex], meaning it is located at the corner of 10th Street and 17th Avenue.

Therefore, the correct answer is:
10th Street and 17th Avenue