Sure, let's solve this problem step-by-step.
We are given:
- The mass of NiS: 57.2 grams
- The number of moles of NiS: 0.63 moles
We need to determine the molar mass of NiS, which will go in the question mark spot in the equation:
[tex]\[57.2 \text{ grams NiS} \times \frac{1 \text{ mol}}{?}=0.63 \text{ mol}\][/tex]
Using the formula:
[tex]\[ \text{Molar mass} = \frac{\text{Mass}}{\text{Moles}} \][/tex]
We substitute the given values:
[tex]\[ \text{Molar mass of NiS} = \frac{57.2 \text{ grams}}{0.63 \text{ moles}} \][/tex]
Let's calculate this:
[tex]\[ \text{Molar mass of NiS} = \frac{57.2}{0.63} \approx 90.75 \text{ grams/mol} \][/tex]
So, the molar mass of NiS is approximately 90.75 grams per mole.
Thus, the correct value to place in the question mark spot is:
[tex]\[90.75 \text{ grams/mol}\][/tex]
The equation now looks like this:
[tex]\[57.2 \text{ grams NiS} \times \frac{1 \text{ mol}}{90.75 \text{ grams/mol}}=0.63 \text{ mol}\][/tex]
So, the correct answer is "90.75 grams."
