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Predict the product:

CH₃-CH₂-CH₂-O-CH₃ + HBr

Sagot :

GinnyAnswer
Certainly! Let's analyze the given chemical reaction:

The reaction is:

[tex]\[ CH_3-CH_2-CH_2-O-CH_3 + HBr \][/tex]

This is a classic example of an ether cleavage reaction with hydrogen bromide (HBr). Ethers can be cleaved by strong acids like HBr into alcohols and alkyl halides.

The ether in question is [tex]\(CH_3-CH_2-CH_2-O-CH_3\)[/tex]. This structure consists of a propyl group [tex]\(CH_3-CH_2-CH_2-\)[/tex] and a methyl group [tex]\(CH_3-\)[/tex] connected via an oxygen atom.

Upon reacting with HBr, the ether will be cleaved:

1. The bond between the oxygen and the carbon attached to the smaller alkyl group (methyl group, [tex]\(CH_3\)[/tex]) will break.
2. Hydrogen from HBr will combine with the methyl group ([tex]\(CH_3\)[/tex]) to form methanol ([tex]\(CH_3OH\)[/tex]).
3. The bromine atom from HBr will attach to the propyl group ([tex]\(CH_3-CH_2-CH_2-\)[/tex]) to form 1-bromopropane ([tex]\(CH_3-CH_2-CH_2Br\)[/tex]).

So, the products of the reaction are:
[tex]\[ CH_3OH \quad \text{(methanol)} \quad \text{and} \quad CH_3-CH_2-CH_2Br \quad \text{(1-bromopropane)} \][/tex]

To summarize, the cleavage of the ether [tex]\(CH_3-CH_2-CH_2-O-CH_3\)[/tex] by HBr produces:

[tex]\[ CH_3OH \quad \text{and} \quad CH_3-CH_2-CH_2Br \][/tex]

These are methanol and 1-bromopropane, respectively.
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