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If 600 J of work is done in 3 s, what is the power? (Power: [tex]\( P = \frac{W}{t} \)[/tex])

A. 0.005 W
B. 200 W
C. 603 W
D. 1800 W


Sagot :

To find the power when [tex]\(600 \, \text{J}\)[/tex] of work is done in [tex]\(3 \, \text{s}\)[/tex], we use the formula for power:

[tex]\[ P = \frac{W}{t} \][/tex]

where
- [tex]\( P \)[/tex] is the power,
- [tex]\( W \)[/tex] is the work done,
- [tex]\( t \)[/tex] is the time taken.

Substitute the given values into the formula:

[tex]\[ W = 600 \, \text{J} \][/tex]
[tex]\[ t = 3 \, \text{s} \][/tex]

Now, calculate the power:

[tex]\[ P = \frac{600 \, \text{J}}{3 \, \text{s}} \][/tex]

[tex]\[ P = 200 \, \text{W} \][/tex]

Therefore, the power is [tex]\( \boxed{200 \, \text{W}} \)[/tex].
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