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Which is not an equation of the line passing through (3,6) and (1,-2)?

A. [tex]\( y - 6 = 4(x - 3) \)[/tex]
B. [tex]\( y + 2 = 4(x - 1) \)[/tex]
C. [tex]\( y - 2 = 4(x + 1) \)[/tex]
D. [tex]\( y = 4x - 6 \)[/tex]

Sagot :

To determine which equation is not the equation of the line passing through the points [tex]\((3, 6)\)[/tex] and [tex]\((1, -2)\)[/tex], let's analyze the situation in detail.

1. Calculate the slope ([tex]\(m\)[/tex]) of the line passing through the points [tex]\((3, 6)\)[/tex] and [tex]\((1, -2)\)[/tex].

The formula for the slope [tex]\(m\)[/tex] is:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Plugging in the coordinates:
[tex]\[ m = \frac{-2 - 6}{1 - 3} = \frac{-8}{-2} = 4 \][/tex]

2. Find the equation of the line using the point-slope form:

The point-slope form of the equation of a line is:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
Using the slope [tex]\(m = 4\)[/tex] and the point [tex]\((3, 6)\)[/tex]:
[tex]\[ y - 6 = 4(x - 3) \][/tex]

Simplifying this equation to the slope-intercept form [tex]\(y = mx + b\)[/tex]:
[tex]\[ y - 6 = 4(x - 3) \][/tex]
[tex]\[ y - 6 = 4x - 12 \][/tex]
[tex]\[ y = 4x - 6 \][/tex]
So, the equation of the line is [tex]\(y = 4x - 6\)[/tex].

3. Verify each given choice by simplifying to see if it matches [tex]\(y = 4x - 6\)[/tex]:

A. [tex]\(y - 6 = 4(x - 3)\)[/tex]
[tex]\[ y - 6 = 4x - 12 \][/tex]
[tex]\[ y = 4x - 6 \][/tex]

This matches the line's equation [tex]\(y = 4x - 6\)[/tex].

B. [tex]\(y + 2 = 4(x - 1)\)[/tex]
[tex]\[ y + 2 = 4x - 4 \][/tex]
[tex]\[ y = 4x - 6 \][/tex]

This matches the line's equation [tex]\(y = 4x - 6\)[/tex].

C. [tex]\(y - 2 = 4(x + 1)\)[/tex]
[tex]\[ y - 2 = 4x + 4 \][/tex]
[tex]\[ y = 4x + 6 \][/tex]

This does NOT match the line's equation [tex]\(y = 4x - 6\)[/tex].

D. [tex]\(y = 4x - 6\)[/tex]

This is already in the correct form and matches the line's equation [tex]\(y = 4x - 6\)[/tex].

The incorrect choice is C. Therefore, the equation that is not the equation of the line passing through the points [tex]\((3, 6)\)[/tex] and [tex]\((1, -2)\)[/tex] is:
~[tex]\[ \boxed{C} \][/tex]