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Sagot :
To solve for [tex]\( f(x) \)[/tex] when [tex]\( x = -5 \)[/tex] given the function [tex]\( f(x) = 5x + 40 \)[/tex], follow these steps:
1. Substitute [tex]\( x = -5 \)[/tex] into the function [tex]\( f(x) \)[/tex].
[tex]\[ f(-5) = 5(-5) + 40 \][/tex]
2. Perform the multiplication inside the parenthesis.
[tex]\[ 5 \times (-5) = -25 \][/tex]
3. Add the result to 40.
[tex]\[ -25 + 40 = 15 \][/tex]
Therefore, [tex]\( f(-5) = 15 \)[/tex].
The correct answer is [tex]\( 15 \)[/tex].
1. Substitute [tex]\( x = -5 \)[/tex] into the function [tex]\( f(x) \)[/tex].
[tex]\[ f(-5) = 5(-5) + 40 \][/tex]
2. Perform the multiplication inside the parenthesis.
[tex]\[ 5 \times (-5) = -25 \][/tex]
3. Add the result to 40.
[tex]\[ -25 + 40 = 15 \][/tex]
Therefore, [tex]\( f(-5) = 15 \)[/tex].
The correct answer is [tex]\( 15 \)[/tex].
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