Tres personas conforman una sociedad:

- Julio apuesta [tex]$51,000
- Pedro apuesta $[/tex]12,000 más que Julio.
- Alejandro apuesta $15,000 menos que Julio.

¿Cuánto apuestan entre los tres?

Question

13-06-2024
Mathematics

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Tres personas conforman una sociedad:

- Julio apuesta [tex]$51,000
- Pedro apuesta $[/tex]12,000 más que Julio.
- Alejandro apuesta $15,000 menos que Julio.

¿Cuánto apuestan entre los tres?

Sagot :

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GinnyAnswer GinnyAnswer · Answer 1 · 2024-06-13T11:07:08-04:00

Claro, vamos a desglosar el problema paso a paso:

1. Identificamos las apuestas de cada persona:
- Julio apuesta [tex]$51360. 2. Calculamos la apuesta de Pedro: - Pedro apuesta $[/tex]12000 más que Julio.
- Entonces, la apuesta de Pedro es [tex]$51360 + $[/tex]12000 = [tex]$63360. 3. Calculamos la apuesta de Alejandro: - Alejandro apuesta $[/tex]15000 menos que Julio.
- Entonces, la apuesta de Alejandro es [tex]$51360 - $[/tex]15000 = [tex]$36360. 4. Sumamos las apuestas de todos para obtener el total: - La apuesta total es la suma de las apuestas de Julio, Pedro y Alejandro. - Entonces, la apuesta total es $[/tex]51360 + [tex]$63360 + $[/tex]36360 = [tex]$151080. Por lo tanto, las apuestas de cada persona y el total apostado por todos ellos es: - Julio: $[/tex]51360
- Pedro: [tex]$63360 - Alejandro: $[/tex]36360
- Total apostado: $151080

Sagot :

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