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Write the coordinates of the vertices after a
translation 8 units left and 1 unit down.
104
У
8-
6
4-
2-
K
L
M
-10 -8 -6 -4 -2 2 4 6 81
K'(
M'
-4-
-6-
-8-
-10


Write The Coordinates Of The Vertices After Atranslation 8 Units Left And 1 Unit Down104У8642KLM10 8 6 4 2 2 4 6 81KM46810 class=

Sagot :

Answer :

  • J' = (-6,-1)
  • K' = (-6,0)
  • L' = (0,0)
  • M' = (0,-1)

Explanation :

a translation of 8 units down means our new x-coordinate would become 8 less units than what it was in initial and one unit left means the y-coordinate would be one unit less than the initial one.

thus,

  • x' = x - 8
  • y' = y - 1
  • vertex' = (x-8,y-1)

hence,

  • J' = (2-8,0-1) = (-6,-1)
  • K' = (2-8,1-1) = (-6,0)
  • L' = (8-8,1-1) = (0,0)
  • M' = (8-8,0-1) = (0,-1)

Answer:

J' = (-6, -1)

K' = (-6, 0)

L' = (0, 0)

M' = (0, -1)

Step-by-step explanation:

The coordinates of the vertices of figure JKLM are:

  • J(2, 0)
  • K(2, 1)
  • L(8, 1)
  • M(8, 0)

In geometry, a translation is a transformation that moves every point of a figure by the same distance in a specified direction without altering its size, shape, or orientation.

When a figure is translated n units left, n is subtracted from its x-coordinate. When a figure is translated n units down, n is subtracted from its y-coordinate.

If figure JKLM is translated 8 units left and 1 unit down, we subtract 8 from the x-coordinates and subtract 1 from the y-coordinates of each vertex of the figure:

(x, y) → (x - 8, y - 1)

Therefore, the coordinates of the vertices after the translation are:

J' = (2 - 8, 0 - 1) = (-6, -1)

K' = (2 - 8, 1 - 1) = (-6, 0)

L' = (8 - 8, 1 - 1) = (0, 0)

M' = (8 - 8, 0 - 1) = (0, -1)

View image semsee45