tay0309
Answered

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Given the reaction:

[tex]\[ 2 \text{NO}(g) + \text{O}_2(g) \rightarrow 2 \text{NO}_2(g) \][/tex]

The theoretical yield of [tex]\(\text{NO}_2\)[/tex] is [tex]\(38.33 \, \text{g}\)[/tex]. The reaction actually generated [tex]\(19.5 \, \text{g}\)[/tex] of [tex]\(\text{NO}_2\)[/tex].

What is the percent yield for the reaction?

[tex]\[ \% \text{ yield} = \frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \% \][/tex]


Sagot :

To determine the percent yield for the reaction, we can follow these steps:

1. Understand the given data:
- The theoretical yield of [tex]\( NO_2 \)[/tex] is [tex]\( 38.33 \)[/tex] grams. The theoretical yield represents the maximum amount of product that can be generated from the given amounts of reactants based on the stoichiometry of the balanced chemical equation.
- The actual yield of [tex]\( NO_2 \)[/tex] is [tex]\( 19.5 \)[/tex] grams. The actual yield is the amount of product actually obtained from the reaction.

2. Formula for percent yield:
The percent yield can be calculated using the formula:
[tex]\[ \text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100 \][/tex]

3. Substitute the values into the formula:
[tex]\[ \text{Percent Yield} = \left( \frac{19.5 \text{ g }}{38.33 \text{ g }} \right) \times 100 \][/tex]

4. Perform the division:
[tex]\[ \frac{19.5}{38.33} \approx 0.508 \][/tex]

5. Multiply by 100 to convert to a percentage:
[tex]\[ 0.508 \times 100 = 50.87398904252544 \][/tex]

Therefore, the percent yield for the reaction is approximately [tex]\( 50.87398904252544\% \)[/tex].