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What is the factored form of [tex]\(a^2 - 121\)[/tex]?

A. [tex]\((a - 121)(a - 1)\)[/tex]
B. [tex]\((a - 11)(a + 11)\)[/tex]
C. [tex]\((a + 11)(a + 11)\)[/tex]
D. [tex]\((a - 121)(a + 1)\)[/tex]


Sagot :

To find the factored form of the expression [tex]\( a^2 - 121 \)[/tex], we can recognize that it fits the pattern of a difference of squares. The general form for factoring a difference of squares is:

[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]

In this case, we can see that:

[tex]\[ a^2 - 121 \][/tex]

First, identify the square roots of the terms:
- [tex]\( a^2 \)[/tex] is [tex]\( (a)^2 \)[/tex]
- [tex]\( 121 \)[/tex] is [tex]\( (11)^2 \)[/tex]

This allows us to rewrite the expression as:

[tex]\[ a^2 - 11^2 \][/tex]

Now, using the difference of squares formula [tex]\( a^2 - b^2 = (a - b)(a + b) \)[/tex], we substitute [tex]\( a \)[/tex] for [tex]\( a \)[/tex] and [tex]\( b \)[/tex] for [tex]\( 11 \)[/tex]:

[tex]\[ a^2 - 11^2 = (a - 11)(a + 11) \][/tex]

So, the factored form of [tex]\( a^2 - 121 \)[/tex] is:

[tex]\[ (a - 11)(a + 11) \][/tex]

Therefore, the correct answer is:

[tex]\[ (a - 11)(a + 11) \][/tex]