Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine the height [tex]\( h \)[/tex] of the rectangular prism given its volume and the area of its base, we use the formula for the volume of a prism, which is given by:
[tex]\[ \text{Volume} = \text{Base Area} \times \text{Height} \][/tex]
Given:
- The volume [tex]\( V \)[/tex] of the rectangular prism: [tex]\( V = x^3 - 3x^2 + 5x - 3 \)[/tex]
- The area of the base [tex]\( A \)[/tex]: [tex]\( A = x^2 - 2 \)[/tex]
To find the height [tex]\( h \)[/tex], we solve for [tex]\( h \)[/tex] in the volume formula:
[tex]\[ h = \frac{V}{A} = \frac{x^3 - 3x^2 + 5x - 3}{x^2 - 2} \][/tex]
We can perform polynomial long division for the given polynomial expression:
[tex]\[ x^3 - 3x^2 + 5x - 3 \div x^2 - 2 \][/tex]
1. Divide the leading term of the numerator [tex]\( x^3 \)[/tex] by the leading term of the denominator [tex]\( x^2 \)[/tex] to get [tex]\( x \)[/tex].
2. Multiply [tex]\( x \)[/tex] by the denominator [tex]\( x^2 - 2 \)[/tex] to get [tex]\( x^3 - 2x \)[/tex].
3. Subtract [tex]\( x^3 - 2x \)[/tex] from [tex]\( x^3 - 3x^2 + 5x - 3 \)[/tex]:
[tex]\[ (x^3 - 3x^2 + 5x - 3) - (x^3 - 2x) = -3x^2 + 7x - 3 \][/tex]
4. Divide the leading term of the new numerator [tex]\( -3x^2 \)[/tex] by the leading term of the denominator [tex]\( x^2 \)[/tex] to get [tex]\( -3 \)[/tex].
5. Multiply [tex]\( -3 \)[/tex] by the denominator [tex]\( x^2 - 2 \)[/tex] to get [tex]\( -3x^2 + 6 \)[/tex].
6. Subtract [tex]\( -3x^2 + 6 \)[/tex] from [tex]\( -3x^2 + 7x - 3 \)[/tex]:
[tex]\[ (-3x^2 + 7x - 3) - (-3x^2 + 6) = 7x - 9 \][/tex]
Thus, the polynomial long division gives us:
[tex]\[ \frac{x^3 - 3x^2 + 5x - 3}{x^2 - 2} = x - 3 + \frac{7x - 9}{x^2 - 2} \][/tex]
Therefore, the height of the prism is:
[tex]\[ x - 3 + \frac{7x - 9}{x^2 - 2} \][/tex]
The correct answer is:
[tex]\[ \boxed{x-3+\frac{7 x-9}{x^2-2}} \][/tex]
[tex]\[ \text{Volume} = \text{Base Area} \times \text{Height} \][/tex]
Given:
- The volume [tex]\( V \)[/tex] of the rectangular prism: [tex]\( V = x^3 - 3x^2 + 5x - 3 \)[/tex]
- The area of the base [tex]\( A \)[/tex]: [tex]\( A = x^2 - 2 \)[/tex]
To find the height [tex]\( h \)[/tex], we solve for [tex]\( h \)[/tex] in the volume formula:
[tex]\[ h = \frac{V}{A} = \frac{x^3 - 3x^2 + 5x - 3}{x^2 - 2} \][/tex]
We can perform polynomial long division for the given polynomial expression:
[tex]\[ x^3 - 3x^2 + 5x - 3 \div x^2 - 2 \][/tex]
1. Divide the leading term of the numerator [tex]\( x^3 \)[/tex] by the leading term of the denominator [tex]\( x^2 \)[/tex] to get [tex]\( x \)[/tex].
2. Multiply [tex]\( x \)[/tex] by the denominator [tex]\( x^2 - 2 \)[/tex] to get [tex]\( x^3 - 2x \)[/tex].
3. Subtract [tex]\( x^3 - 2x \)[/tex] from [tex]\( x^3 - 3x^2 + 5x - 3 \)[/tex]:
[tex]\[ (x^3 - 3x^2 + 5x - 3) - (x^3 - 2x) = -3x^2 + 7x - 3 \][/tex]
4. Divide the leading term of the new numerator [tex]\( -3x^2 \)[/tex] by the leading term of the denominator [tex]\( x^2 \)[/tex] to get [tex]\( -3 \)[/tex].
5. Multiply [tex]\( -3 \)[/tex] by the denominator [tex]\( x^2 - 2 \)[/tex] to get [tex]\( -3x^2 + 6 \)[/tex].
6. Subtract [tex]\( -3x^2 + 6 \)[/tex] from [tex]\( -3x^2 + 7x - 3 \)[/tex]:
[tex]\[ (-3x^2 + 7x - 3) - (-3x^2 + 6) = 7x - 9 \][/tex]
Thus, the polynomial long division gives us:
[tex]\[ \frac{x^3 - 3x^2 + 5x - 3}{x^2 - 2} = x - 3 + \frac{7x - 9}{x^2 - 2} \][/tex]
Therefore, the height of the prism is:
[tex]\[ x - 3 + \frac{7x - 9}{x^2 - 2} \][/tex]
The correct answer is:
[tex]\[ \boxed{x-3+\frac{7 x-9}{x^2-2}} \][/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.