Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 120°?

A. 720°
B. 180°
C. 900°
D. 1080°
E. 540°
F. 360°

Sagot :

To determine the sum of the measures of the interior angles of a regular polygon where each exterior angle measures [tex]\(120^\circ\)[/tex], follow these steps:

1. Determine the number of sides of the polygon:
- Recall that the sum of the exterior angles of any polygon is always [tex]\(360^\circ\)[/tex].
- Since each exterior angle measures [tex]\(120^\circ\)[/tex], we can find the number of sides [tex]\(n\)[/tex] by dividing the sum of the exterior angles by the measure of one exterior angle.
[tex]\[ n = \frac{360^\circ}{120^\circ} = 3 \][/tex]

2. Calculate the sum of the interior angles:
- The formula for the sum of the interior angles of a polygon is [tex]\((n - 2) \times 180^\circ\)[/tex], where [tex]\(n\)[/tex] is the number of sides.
- Substitute [tex]\(n = 3\)[/tex] into the formula:
[tex]\[ \text{Sum of interior angles} = (3 - 2) \times 180^\circ = 1 \times 180^\circ = 180^\circ \][/tex]

Therefore, the sum of the measures of the interior angles of the polygon is [tex]\(\boxed{180^\circ}\)[/tex].