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Simplify [tex]\(\frac{\sqrt[3]{7}}{\sqrt[5]{7}}\)[/tex]:

A. [tex]\(7^{\frac{1}{5}}\)[/tex]

B. [tex]\(7^{\frac{8}{15}}\)[/tex]

C. [tex]\(7^{\frac{5}{3}}\)[/tex]

D. [tex]\(7^{\frac{2}{15}}\)[/tex]


Sagot :

To simplify the expression [tex]\(\frac{\sqrt[3]{7}}{\sqrt[5]{7}}\)[/tex], we need to handle the exponents involved and simplify accordingly.

First, let's express the radicals in exponent form:
[tex]\[ \sqrt[3]{7} = 7^{\frac{1}{3}} \][/tex]
[tex]\[ \sqrt[5]{7} = 7^{\frac{1}{5}} \][/tex]

Now, let's rewrite the given expression [tex]\(\frac{\sqrt[3]{7}}{\sqrt[5]{7}}\)[/tex] using these exponents:
[tex]\[ \frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}} \][/tex]

When we divide powers with the same base, we subtract the exponents:
[tex]\[ 7^{\frac{1}{3} - \frac{1}{5}} \][/tex]

To subtract these fractions, we need a common denominator. The least common multiple of 3 and 5 is 15. So we convert both fractions to have a denominator of 15:
[tex]\[ \frac{1}{3} = \frac{5}{15} \][/tex]
[tex]\[ \frac{1}{5} = \frac{3}{15} \][/tex]

Now, subtract the exponents:
[tex]\[ \frac{5}{15} - \frac{3}{15} = \frac{2}{15} \][/tex]

This gives us the simplified exponent:
[tex]\[ 7^{\frac{2}{15}} \][/tex]

Thus, the simplified form of the expression [tex]\(\frac{\sqrt[3]{7}}{\sqrt[5]{7}}\)[/tex] is:
[tex]\[ 7^{\frac{2}{15}} \][/tex]

Among the given choices:
1. [tex]\(7^{\frac{1}{5}}\)[/tex]
2. [tex]\(7^{\frac{8}{15}}\)[/tex]
3. [tex]\(7^{\frac{5}{3}}\)[/tex]
4. [tex]\(7^{\frac{2}{15}}\)[/tex]

The correct answer is:
[tex]\[ 7^{\frac{2}{15}} \][/tex]