Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

What is the domain of the function [tex]\( y = 2 \sqrt{x-6} \)[/tex]?

A. [tex]\(-\infty \ \textless \ x \ \textless \ \infty\)[/tex]
B. [tex]\(0 \leq x \ \textless \ \infty\)[/tex]
C. [tex]\(3 \leq x \ \textless \ \infty\)[/tex]
D. [tex]\(6 \leq x \ \textless \ \infty\)[/tex]


Sagot :

To determine the domain of the function [tex]\( y = 2 \sqrt{x - 6} \)[/tex], we need to ensure that the expression inside the square root is non-negative. The square root function is only defined for non-negative values, meaning that the input must be zero or positive.

Given the function [tex]\( y = 2 \sqrt{x - 6} \)[/tex], the expression inside the square root is [tex]\( x - 6 \)[/tex]. So, we need:

[tex]\[ x - 6 \geq 0 \][/tex]

Solving this inequality for [tex]\( x \)[/tex] gives:

[tex]\[ x \geq 6 \][/tex]

This means that the function is defined for all values of [tex]\( x \)[/tex] starting from 6 and extending to infinity. In interval notation, we write this as:

[tex]\[ 6 \leq x < \infty \][/tex]

Therefore, the correct option that represents the domain of the function [tex]\( y = 2 \sqrt{x - 6} \)[/tex] is:

[tex]\[ 6 \leq x < \infty \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.