At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To find the range of [tex]\((w \circ r)(x)\)[/tex], we need to determine the composition of the functions [tex]\(w(x)\)[/tex] and [tex]\(r(x)\)[/tex]. The composition [tex]\(w(r(x))\)[/tex] involves substituting [tex]\(r(x)\)[/tex] into [tex]\(w(x)\)[/tex].
Given:
[tex]\[ r(x) = 2 - x^2 \][/tex]
[tex]\[ w(x) = x - 2 \][/tex]
First, let's find [tex]\(w(r(x))\)[/tex]:
[tex]\[ w(r(x)) = w(2 - x^2) \][/tex]
Since [tex]\(w(x)\)[/tex] is defined as [tex]\(x - 2\)[/tex], substitute [tex]\(2 - x^2\)[/tex] into [tex]\(w\)[/tex]:
[tex]\[ w(2 - x^2) = (2 - x^2) - 2 \][/tex]
[tex]\[ w(2 - x^2) = 2 - x^2 - 2 \][/tex]
[tex]\[ w(2 - x^2) = -x^2 \][/tex]
Next, we need to determine the range of the function [tex]\(w(r(x)) = -x^2\)[/tex].
The quadratic function [tex]\(-x^2\)[/tex] opens downwards because the coefficient of [tex]\(x^2\)[/tex] is negative. For any real number [tex]\(x\)[/tex], [tex]\(x^2\)[/tex] is always non-negative (i.e., [tex]\(x^2 \geq 0\)[/tex]). Therefore, [tex]\(-x^2\)[/tex] will be non-positive and will achieve its maximum value at 0 when [tex]\(x = 0\)[/tex].
Thus, [tex]\(-x^2\)[/tex] for all real [tex]\(x\)[/tex] takes all values in the interval [tex]\((-\infty, 0]\)[/tex].
Therefore, the range of [tex]\((w \circ r)(x)\)[/tex] is:
[tex]\[ \boxed{(-\infty, 0]} \][/tex]
Given:
[tex]\[ r(x) = 2 - x^2 \][/tex]
[tex]\[ w(x) = x - 2 \][/tex]
First, let's find [tex]\(w(r(x))\)[/tex]:
[tex]\[ w(r(x)) = w(2 - x^2) \][/tex]
Since [tex]\(w(x)\)[/tex] is defined as [tex]\(x - 2\)[/tex], substitute [tex]\(2 - x^2\)[/tex] into [tex]\(w\)[/tex]:
[tex]\[ w(2 - x^2) = (2 - x^2) - 2 \][/tex]
[tex]\[ w(2 - x^2) = 2 - x^2 - 2 \][/tex]
[tex]\[ w(2 - x^2) = -x^2 \][/tex]
Next, we need to determine the range of the function [tex]\(w(r(x)) = -x^2\)[/tex].
The quadratic function [tex]\(-x^2\)[/tex] opens downwards because the coefficient of [tex]\(x^2\)[/tex] is negative. For any real number [tex]\(x\)[/tex], [tex]\(x^2\)[/tex] is always non-negative (i.e., [tex]\(x^2 \geq 0\)[/tex]). Therefore, [tex]\(-x^2\)[/tex] will be non-positive and will achieve its maximum value at 0 when [tex]\(x = 0\)[/tex].
Thus, [tex]\(-x^2\)[/tex] for all real [tex]\(x\)[/tex] takes all values in the interval [tex]\((-\infty, 0]\)[/tex].
Therefore, the range of [tex]\((w \circ r)(x)\)[/tex] is:
[tex]\[ \boxed{(-\infty, 0]} \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.