To determine the value of [tex]\( f(-2) \)[/tex] from the given function table, we need to locate the row where [tex]\( x = -2 \)[/tex] and then find the corresponding [tex]\( f(x) \)[/tex] value.
Here is the table again for reference:
[tex]\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-6 & 3 \\
\hline
-2 & 1 \\
\hline
0 & 4 \\
\hline
3 & -2 \\
\hline
\end{array}
\][/tex]
Looking at the table:
- When [tex]\( x = -6 \)[/tex], [tex]\( f(x) = 3 \)[/tex]
- When [tex]\( x = -2 \)[/tex], [tex]\( f(x) = 1 \)[/tex]
- When [tex]\( x = 0 \)[/tex], [tex]\( f(x) = 4 \)[/tex]
- When [tex]\( x = 3 \)[/tex], [tex]\( f(x) = -2 \)[/tex]
So, we need to find [tex]\( f(-2) \)[/tex]:
When [tex]\( x = -2 \)[/tex], [tex]\( f(x) = 1 \)[/tex].
Therefore, [tex]\( f(-2) \)[/tex] is 1.
So, the correct answer is [tex]\( 1 \)[/tex].
