To determine the heat required to vaporize 650 grams of a liquid with a heat of vaporization of 723 joules/gram, follow these steps:
1. Identify the given data:
- Mass of the liquid ([tex]\( m \)[/tex]): [tex]\(650\)[/tex] grams
- Heat of vaporization ([tex]\( L \)[/tex]): [tex]\(723\)[/tex] joules/gram
2. Use the formula for calculating the heat required to vaporize a given mass:
[tex]\[
Q = m \times L
\][/tex]
where [tex]\( Q \)[/tex] is the heat required, [tex]\( m \)[/tex] is the mass, and [tex]\( L \)[/tex] is the heat of vaporization.
3. Substitute the values into the formula:
[tex]\[
Q = 650 \, \text{grams} \times 723 \, \text{joules/gram}
\][/tex]
4. Calculate the result:
[tex]\[
Q = 469950 \, \text{joules}
\][/tex]
Thus, the heat required to vaporize 650 grams of the liquid is [tex]\( 469950 \)[/tex] joules.
Given the options:
- A: [tex]\( 0.90 \, \text{J} \)[/tex]
- B: [tex]\( 1.1 \, \text{J} \)[/tex]
- C: [tex]\( 73 \, \text{J} \)[/tex]
- D: [tex]\( 1,370 \, \text{J} \)[/tex]
- E: [tex]\( 470,000 \, \text{J} \)[/tex]
The correct answer, rounding to match the options provided, is:
E. 470,000 J.
