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The price of a movie ticket in a given year can be modeled by the regression equation [tex]\( y = 6.94 \times (1.02^x) \)[/tex], where [tex]\( y \)[/tex] is the ticket price and [tex]\( x \)[/tex] is the year.

To the nearest cent, which is the best prediction of the price of a ticket in year 20? (Year 1 = 2007)

A. \[tex]$266.06
B. \$[/tex]10.31
C. \[tex]$11.39
D. \$[/tex]12.57


Sagot :

To predict the price of a movie ticket in year 20 using the given regression equation [tex]\( y = 6.94 \cdot (1.02^x) \)[/tex], follow these steps:

1. Identify the given parameters in the regression equation:
[tex]\[ y = 6.94 \cdot (1.02^x) \][/tex]
Here, [tex]\( 6.94 \)[/tex] is the base price in 2007 (year 0), [tex]\( 1.02 \)[/tex] is the growth rate, and [tex]\( x \)[/tex] is the number of years since 2007.

2. Determine the value of [tex]\( x \)[/tex] for year 20:
[tex]\[ x = 20 \][/tex]
This represents the year 2027 because [tex]\( 2007 + 20 = 2027 \)[/tex].

3. Substitute [tex]\( x = 20 \)[/tex] into the regression equation:
[tex]\[ y = 6.94 \cdot (1.02^{20}) \][/tex]

4. Calculate [tex]\( (1.02^{20}) \)[/tex], which is approximately 1.485947:
[tex]\[ 1.02^{20} \approx 1.485947 \][/tex]

5. Multiply this factor by the base price of the ticket:
[tex]\[ y = 6.94 \cdot 1.485947 \approx 10.312474928089783 \][/tex]

6. Round the result to the nearest cent:
[tex]\[ y \approx \$10.31 \][/tex]

Therefore, the best prediction of the price of a movie ticket in year 20 (2027) is [tex]\(\$10.31\)[/tex].

Hence, the correct answer is:
B. [tex]$\$[/tex] 10.31$